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Trava [24]
3 years ago
9

Use the spinner below for each of the following

Mathematics
1 answer:
spayn [35]3 years ago
3 0
The answer is : impossible
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Write a word phrase to represent the numerical expression below.<br><br> 5+(17-8)
Klio2033 [76]

Answer:

Step-by-step explanation:

So ,to create a word phrase, you have to identify all of the operations going on here...

5+(17 - 8)

within the parentheses, you have subtraction. that's usually called the "difference" in word phrases. you also have a 5 outside the parentheses, leaving it to be multiplied inside, and multiplication is typically referred to as a "product"

with that info, you can construct a word phrase such as "the product of 5 and the difference between 17 and 8" or "the difference between 17 and 8 multiplied by 5"

6 0
3 years ago
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What is the measure of angle D?<br><br> 52<br> 54<br> 57<br> 126
Fudgin [204]

Answer: 52

Step-by-step explanation:

7 0
3 years ago
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Venla is 5 years older than her cousin Kora.
AfilCa [17]

Answer:

13

Step-by-step explanation:

v=k+5

k=Kora's age

if v=18

k=v-5

k=18-5

j=13

7 0
3 years ago
Herr is a balance hanger diagram a circle has a mass of three grams and a square has a mass of two grams which is the mass of th
Naily [24]

The hanger diagram ideally should be in balance with all the shapes hung on it.

On the left side, it shows that the circles are 9 grams and the squares are 12 grams. The triangles are 2t grams. Therefore, on the left side we have,

9 + 12 + 2t

On the right side, it shows the circles are 6 grams and the squares are 6 grams, while the triangles are 5t grams. Therefore on the right side we have

6 + 6 + 5t.

For the hanger to be in balance, we should have

undefined

3 0
1 year ago
Please help me out with this
olga_2 [115]

Answer:

10.4 cm

Step-by-step explanation:

The volume (V) of a pyramid is calculated using

V = \frac{1}{3} area of base × height (h)

area of square base = 6² = 36, thus

\frac{1}{3} × 36h = 120

12h = 120 ( divide both sides by 12 )

h = 10 cm

To find the slant height (s) consider the right triangle from the vertex to the midpoint of the base and from the midpoint of base to the side.

That is a right triangle with hypotenuse s and legs 10(h) and 3 (midpoint of the base )

Using Pythagoras' identity then

s² = 10² + 3² = 100 + 9 = 109

Take the square root of both sides

s = \sqrt{109} ≈ 10.4 cm

3 0
3 years ago
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