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3 years ago

could someone out there perhaps help me? i’m so lost even though it’s probably so simple. i’ll give you brainleist :)

Mathematics

1 answer:

Temka [501]3 years ago

8 0

Answer:

y= -x+7, b= sqrt(2P/a), c=3P^2-b

Step-by-step explanation:

First, make a table regarding both of the equations. You will eventually find out that both lines intersect at the point (2, 5) after you find the points on the table. From there, subtract x from both sides in the equation x + y = 2. You will get y = -x + 2. Since they said the line was parallel, find a line that has the slope of negative one. Since we know that this line intersects the point in which the first two lines intersect, we know that the y-intercept will be 7. The equation of the line would be y=-x+7.

Multiply both sides by 2. Then, divide both sides by a to get b^2=(2P/a). Take the square root to get the value of b, which is sqrt(2P/a).

Square both sides of the equation to get P^2=(b+c)/3. Cross multiply to get 3P^2=b+c. Subtract b from both sides to get c=3P^2-b.

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Ken paid for $12 for two magazines. The cost of each magazine was a multiple of 3. What is Mare the possible prices of the magaz

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Answer:

So the possibilities are

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Step-by-step explanation:

Given:

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First possible price $12 and $0

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So the possibilities are

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2 years ago

Whats the answer to -x² +6x + 18 = 0

emmainna [20.7K]

Answer:

Step-by-step explanation:

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<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

$(4k + 159)^{\circ}$

And another arc, let's call it FGH. measures:

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If those arc are equal, then this equation is true:

$(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3$

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2 years ago

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Alisiya [41]

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All members of a class of 27 students participated in at least one event on sports day. 20 students participated in individual e

creativ13 [48]

5 students took part in both individual and team events.

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Given:

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