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SVETLANKA909090 [29]

3 years ago

10

Of all the Sunny Club members in a particular city, 25% prefer swimming on weekends and 75% prefer swimming on weekdays. It is f

ound that 10% of the members in that city prefer swimming on weekends and are female, while 55% of the members in that city prefer swimming on weekdays and are female.
The probability that a club member picked randomly is female, given that the person prefers swimming on weekends, is .
a .19
b .20
c .24
d .40

2 answers:

hichkok12 [17]3 years ago

5 0

The answer is D) 40 .

baherus [9]3 years ago

3 0

The answer should be d) 40

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How many ways can a 7 question multiple choice test be answered? (assume that there are 5 possible responses per question?

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I am assuming that you can only pick one answer per question.

Let's imagine there are two questions on the test. I would:

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2) Consider the second question. How many ways can you answer that?

If you wrote out all the possibilities, how many combinations of answers would you get across the two questions?

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3 years ago

12 - 16 ÷(-4)<br><br> A. -1<br> B. 1<br> C. 8<br> D. 16

Naya [18.7K]

Answer:

D. 16

Step-by-step explanation:

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3 years ago

Which equation represents a line that passes through (5, 1) and has a slope of 1/2?

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Answer:

C

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

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3 years ago

3/4x + 11 < .3x + 3/4<br><br>Solve inequality. pls

Rashid [163]

<span><span><span><span>3/4</span>x</span>+11 </span>< <span><span>0.3x</span>+<span>3/4
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.75x+11 < 0.3x+.75
And then subtract 0.3x from both sides to get
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4 years ago

A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The plate, including the bound

rjkz [21]

Answer:

We have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . and the hottest value is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

$T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x$

Let's take the partials derivatives.

$T_{x}(x,y)=2x-\frac{3}{2}=0$

$T_{y}(x,y)=4y=0$

So, we can find the critical point (x,y) of T(x,y).

$2x-\frac{3}{2}=0$

$x=\frac{3}{4}$

$4y=0$

$y=0$

The critical point is (3/4,0) so the temperature at this point is: $T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})$

$T(\frac{3}{4},0)=-\frac{9}{16}$

Now, we need to evaluate the boundary condition.

$x^{2}+y^{2}=1$

We can solve this equation for y and evaluate this value in the temperature.

$y=\pm \sqrt{1-x^{2}}$

$T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x$

$T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2$

Now, let's find the critical point again, as we did above.

$T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0$

$x=-\frac{3}{4}$

Evaluating T(x,y) at this point, we have:

$T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2$

$T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$

Now, we can see that at point (3/4,0) we have the coldest value of temperature $T(\frac{3}{4},0) = -9/16$ . On the other hand, at the point $-(3/4),\frac{\sqrt{7}}{4})$ we have the hottest value of temperature, it is $T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}$ .

I hope it helps you!

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3 years ago