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tester [92]
2 years ago
7

Can someone help me please

Mathematics
2 answers:
Pavel [41]2 years ago
6 0
-8 that is the answere it was easy
Andre45 [30]2 years ago
3 0
The equation for this table is y = -4x + 17.
To find y when x = 0, plug in 0 for x and solve.
y = -4(0) + 17
y = 17
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Option 1:<br><br> Find x. Show all work.
Ronch [10]

Using law of cosines:

Cos(angle) = adjacent/ hypotenuse


Cos(22) = 12/x

Rewrite to get:

X = 12/cos(22)

Simplify:

X = 12.9424

Round the answer as needed.

5 0
2 years ago
Read 2 more answers
Brad earns a base monthly salary of $2,200 plus $1.1% commission on his total sales. Let s be Brad's total sales.
Lelechka [254]
I think it’s like that but u shld wait for someone else to answer, cuz i’m not sure if im correct cuz the ans is so big

3 0
2 years ago
24 ÷ v x k when v=2 and k=4
Leya [2.2K]

Answer:

48

Step-by-step explanation:

24 ÷ v x k

24 ÷ 2 x 4    

(Since it's multiplication and division, you just go from left to right in order)

12 x 4

48

5 0
3 years ago
Is the binomial a factor of the polynomial nominal function?
Sedbober [7]

The factors for given equation f(x)=x^{3} +3x^{2} -25x-75.

  • (x-1) - No
  • (x-3) - No
  • (x+3) - Yes
  • (x-5) - Yes
  • (x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)=x^{3} +3x^{2} -25x-75 .

Add 0 at the end of the equation.

x^{3} +3x^{2} -25x-75 = 0.

Let us group the given equation,

(x^{3} +3x^{2}) -(25x-75) =0.

⇒ Group 1: x^{3} +3x^{2} .

Group 2: - 25x +75 .

Pull out factor from each group,

⇒ Group 1: (x+3)(x^{2}).

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

(x+3)(x^{2} -25) =0.

One of the factor is (x+3).

Other factors are solved by the formula, a^{2}-b^{2} = (a+b) (a-b) .

(x+3)(x^{2} -25) = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0
3 years ago
Explain why 7* x/7=x 7 times x over seven. why is it x?
Nikolay [14]
It is 1 because if you divided 7over 7 it 1 so x=1
5 0
3 years ago
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