Ask question

Ask question

All categories

3 years ago

13

If

{1}{7} x +\frac{1}{3} y=4" alt="\frac{1}{7} x +\frac{1}{3} y=4" align="absmiddle" class="latex-formula">, then what does 3x + 7y equal?
A.) 21
B.) 84
C.) -21
D.) 10

2 answers:

NemiM [27]3 years ago

6 0

B is the answer to the question

Y_Kistochka [10]3 years ago

4 0

B would be the answer html bit

You might be interested in

Is the graph a linear function, no name and function, or relation (non-functioning)?

lozanna [386]

Answer:

no name and function

Step-by-step explanation:

7 0

3 years ago

Determine whether

Alina [70]

Answer:

Grade 8 Worktext-Science Quarter 3

3 0

3 years ago

3x6 distributive property

Trava [24]

Cannot be applied on a single factor.

Hope this helps.

8 0

4 years ago

PLEASE anyone I need help

Reptile [31]

Answer:

1 34

2 45

3 23

Step-by-step explanation:

8 0

3 years ago

Solve equation by the quadratic formula. List the solutions, separated by commas.<br> 4r^2 +3r+10=8

slega [8]

Answer:

$-\frac{3}{8} +\frac{\sqrt[]{23}i }{8},-\frac{3}{8} -\frac{\sqrt[]{23}i }{8}$

or

$-0.375+0.599479i,-0.375-0.599479i$

Step-by-step explanation:

$4r^2+3r+10=8$

Bring the 8 to the left side so that we equal the equation to 0. To do this, simply substract 8 on both sides.

$4r^2+3r+10-8=8-8\\4r^2+3r+2=0$

Where;

$a=4\\b=3\\c=2$

$Formula: x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac} }{2a}$

Replace. Let x be r

$r=\frac{-3\frac{+}{}\sqrt[]{(3)^2-4(4)(2)} }{2(4)}$

$r=\frac{-3\frac{+}{}\sqrt[]{9-32} }{8}$

$r=\frac{-3\frac{+}{}\sqrt[]{-23} }{8}$

It has no real solution because the square root is negative.

We can say that,

$r=-\frac{3}{8} \frac{+}{}\frac{\sqrt[]{23}*\sqrt[]{-1} }{8}$

$r=-\frac{3}{8} \frac{+}{}\frac{\sqrt[]{23}i }{8}$

$r_1=-0.375+0.599479i\\r_2=-0.375-0.599479i$

5 0

3 years ago