Answer:
if sin (x-3) degrees = cos (2x+6) degrees, find the value of x.
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Note: sin and cos are complementary functions....
sin(x) = cos (90-x)
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Your Problem:
sin(x-3) = cos(90-(x-3))
Equation:
90-[x-3] = 2x+6
90-x+3 = 2x+6
3x = 93-6
x = 31-2
x = 29
Step-by-step explanation:
Answer:
OA) 14
Step-by-step explanation:
2((7+1)-1)
2(8-1)
You could expand the brackets then simplify or just simplify now. It will be better to simplify now though but I will do both methods.
Simplifying first:
2(7) = 2 × 7 = 14
Our answer is 14 So answer is OA) 14
Expanding first then simplifying:
2(8-1) = 16-2 = 14
Our answer is 14 So answer is OA) 14
Use the Pythagorean theorem. The equation for this right triangle would be a^2+b^2=c^2. Since you have one leg and the hypotenuse, you can plug these into the equation. It would be 7^2+b^2=12^2. Do the exponents. You will get 49+b^2=144. You need to get b by itself so subtract each side by 49. You get the equation b^2=95. Square root each side to get b=9.746. This rounds to 9.7. So the answer is A. Hope this helps! ;)
