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kolezko [41]
2 years ago
12

FREEEEEEEEEEEEEEEEE POINTS

Mathematics
2 answers:
notsponge [240]2 years ago
6 0

Answer:

Thank you so much

Step-by-step explanation:

Mashcka [7]2 years ago
5 0

Answer: tysm

Step-by-step explanation:

I needed points to get an answer but didactic have enough

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Find the length of h. Round your answer to the hundredths place if you get a decimal
Luda [366]

Answer:

sheeeeeeeeeeeeeesh

Step-by-step explanation:

7 0
3 years ago
What is equivalent to<br>x2+ 14x = -13​
postnew [5]

Answer:

X= 1 AND 13

Step-by-step explanation:

x2+14x = -13

by completing the square method

you add the square of half the coefficient of b to both sides

which is (14/2)^2

x^2+14x+(7^2) = -13 +(7^2)

x^2 + 7^2 = -13 + 49

x^2 + 7^2 = 36

(x + 7)^2 = 36

find the square root of both sides

(x+7) = + or - 6

x=7-6 ; 1

or

x= 7+6 ; 13

8 0
2 years ago
Kevin has $24 to buy a gift for his cousin he found a gift for $22 with a 5% sales tax added on will Kevin have enough money to
STatiana [176]

Kevin will have enough. He will need to pay $23.10.

5% of $22 is $1.10.

22+1.10=23.10

23.10 is less than 24

6 0
3 years ago
A violin student records the number of hours she spends practicing during each of nine consecutive weeks: 6.2 5.0 4.3 7.4 5.8 7.
spin [16.1K]

Answer:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

Step-by-step explanation:

Assuming this complete question: A violin student records the number of hours she spends practicing during each of nine consecutive weeks:

6.2 5.0 4.3 7.4 5.8 7.2 8.4 1.2 6.3

For this case we need to sort the data first on increasing way and we got:

1.2, 4.3, 5.0, 5.8, 6.2, 6.3, 7.2, 7.4, 8.4

For this case we have 9 values the median would be on the 5 position:

Median = 6.2

The first quartile would be 5 since we analyze 1.2, 4.3, 5.0, 5.8, 6.2 and the middle point is 5.0

The third quartile would be 7.2 since we analyze 6.2, 6.3, 7.2, 7.4, 8.4 and the middle point is 7.2

Then the interquartile rnage would be:

IQR = Q_3 -Q_1= 7.2-5=2.2

And 1.5 IQR = 1.5*2.2=3.3

The lower limit on this case would be:

LL= Q_1 -1.5 IQR= 5-3.3=1.7

And our value is 1.2 is lower than the lower limit 1.7

Considering the smallest data value (1.2) and using the 1.5 × IQR rule, we would:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first  quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

B) not classify the value 1.2 as an outlier, because it is not more than 1.5 × IQR below  the first quartile.

False 1.2 is more than 1.5 IQR below the first quartile

C) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  median.

False, we analyze if is an outlier comparing with the Q1 or Q3 not with the median

D) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the  mean.

False we analyze if is an outlier comparing with the Q1 or Q3 not with the mean

5 0
3 years ago
Rewrite 2 2/5 as an improper fraction. helpp
vesna_86 [32]

Answer: 12\5 :)

Step-by-step explanation: :)

3 0
3 years ago
Read 2 more answers
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