When I factor[ 2cos (square) - 5cos -3], I get (2cos + 1)(cos - 3). 2cos + 1 = 0, 2cos = -1, cos = -0.5,. Using inv cos on calculator, I get 120 degree related angle.
In here, we will use the distance formula
Compute the distance between <span>(-5, 3) and (5, 3)
</span>
<span>
= 10
The distance between </span>(-5, 3) and (5, 3) is 10
Answer:
6,535.06 feet
Step-by-step explanation:
The set up is right angles
hypotenuse = 7000feet
angle of elevation = 21 degrees
Required
horizontal distance (adjacent)
Using SOH, CAH TOA trig identity
cos theta = adj/hyp
cos 21 = adj/7000
adj = 7000 cos 21
adj = 7000(0.9336)
adj = 6,535.06
Hence the HORIZONTAL distance until the plane flies over the island is 6,535.06 feet
Answer:
y = -3/4x - 3
Step-by-step explanation:
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Answer:
7. 23
8. 18
9. 55
10. 17
Step-by-step explanation:
