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creativ13 [48]
3 years ago
12

If the cubic function P(x) includes the points (−1, 0), (−2, 0), (3, 0), and (0, −12) which of the following represents this fun

ction?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0
I think the answer would be <span>2(x + 1)(x + 2)(x - 3).
Hope this helped! :) </span>
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Given the cost function, C(x), and the revenue function, R(x), find the number of units x that must be sold to break even
tresset_1 [31]
P(x) = R(x) - C(x) Breaking even is the point where revenue starts to overtake cost.  It is, therefore, the point where P(x) = 0.  Since these are all linear functions, you know that after that point the business is profitable.  P(x) = 0R(x) - C(x) = 015000x - (9000x+72000) = 015000x - 9000x - 72000 = 06000x - 72000 = 06000x = 72000x = 72000/6000x = 12 At 12 units the business breaks even.
8 0
3 years ago
The cone has a diameter of 6 inches and a base diameter of 4 inches. What is the volume of the cone in cubic inches? A) 8pi B) 1
yuradex [85]

Answer:

Step-by-step explanation:

The formula for the volume of a cone is

V = (1/3)r²h, where r is the radius and h is the height.

Unfortunately, you seem to have given the diameter twice.  

Which is the diameter of the base, 6 inches or 4 inches?  What is the height of the cone, in inches?

7 0
3 years ago
Calculate the income needed based on the following budgeted expenses.
Lynna [10]
Hope this helped you :)
5 0
3 years ago
In triangle ABC, P is a centroid on a median AD. If AD=33 and AP&gt;PD find AP
jasenka [17]

Answer:

AP = 22

Step-by-step explanation:

In a triangle, the centroid divides the median in the ratio 2:1.

It is given that AD is the median and AD = 33

It is also given that P is the centroid on the median AD.

Therefore, P divides AD in the ratio 2:1.

\frac{AP}{PD} =\frac{2}{1}

AP = 2k and PD = k

AD = 33

AP + PD = 33

2k + k = 33

3k = 33

k = 11

So, AP = 2k = 2(11) = 22

7 0
3 years ago
Anybody? need help asap
VladimirAG [237]

Answer:

<em>K</em>=<em>2h</em>

<em>k</em><em>=</em><em>0.5h</em>

<em>k</em><em>=</em><em>h</em><em> </em><em>+</em><em> </em><em>1</em>

<em>k</em><em>=</em><em> </em><em>0.5h</em><em> </em><em>+</em><em> </em><em>1</em><em>0</em>

7 0
2 years ago
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