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11Alexandr11 [23.1K]

2 years ago

9

Vera is using her phone . It’s battery is down to 1/2 and it drains another 1/8 every hour . How many hour will her battery last

?

1 answer:

attashe74 [19]2 years ago

3 0

4 hours because 1/2 equals 4/8 and it takes 4/8, so four hours, more to be gone

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Answer:

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2 years ago

−9(x + 6) + 60 = 13 − 10x

GREYUIT [131]

Answer:

X=7

Step-by-step explanation:

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The amount of gasoline that 80 drivers bought to fill their cars’ gas tanks is shown. How many drivers bought more than 12 gallo

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2 years ago

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mart [117]

Answer:

41. f⁻¹(x) = -9x + 4

43. m⁻¹(x) = ∛(x-2)/4

Step-by-step explanation:

41. y = (4-x)/9

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solve y: 9x = 4-y

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x = 4y³+2

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5 0

3 years ago

In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat

monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

$f(t) = 10000(0.9407)^t$

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

$f(t) = f(0)(1-r)^t$

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that $f(0) = 10000$ , thus:

$f(t) = 10000(1-r)^t$

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

$f(2) = 8850$

We use this to find 1 - r.

$f(t) = 10000(1-r)^t$

$8850 = 10000(1-r)^2$

$(1-r)^2 = \frac{8850}{10000}$

$(1-r)^2 = 0.885$

$\sqrt{(1-r)^2} = \sqrt{0.885}$

$1 - r = 0.9407$

Thus

$f(t) = 10000(1-r)^t$

$f(t) = 10000(0.9407)^t$

7 0

2 years ago