All categories

3 years ago

How can one sixthx − 5 = one fifthx + 2 be set up as a system of equations?

Mathematics

2 answers:

Len [333]3 years ago

7 0

Answer:

6y - x = -30 and 5y - x = 10

Step by Step:

They want you to remove the fractions from the x-values. How can we remove the 1/6 from the x in the first equation? We can multiply the entire equation (both sides) by 6 because it cancels out the 1/6 found in the x-value. This achieves 6y = x - 30 for our first equation. This can be changed to 6y - x = -30.

How can we remove the 1/5 from the x-value in the second equation? We can multiply the entire equation by 5, since that cancels with the 1/5 coefficient found in the x-value. This gets us 5y = x + 10. This can be changed to meet our answer choices to 5y - x = 10.

s2008m [1.1K]3 years ago

5 0

For problems like these, we can set both sides of the equation equal to y. This is because both sides of the equation are equal to each other. If we were to take the left side of the equation and set it equal to y, the right side would also be equal to y. Similarly, if we were to set the right side of the equation equal to y, the left side of the equation would also be equal to y. Setting both equations equal to y will produce two equations which can be used in a system of equations.

Thus, our answer is:
y = (1/6)x - 5
y = (1/5)x + 2

You might be interested in

Someone help pls I forgot how to do it

yawa3891 [41]

(2,4)

Step-by-step explanation:

I'm not sure in the slightest but with the formula I learned I think this is correct

3 0

3 years ago

Harry is trying to solve the equation 0 = 2x2 − x − 6 using the quadratic formula. He has made an error in one of the steps belo

bija089 [108]

<h3><u>Given</u> - </h3>

➙ a quadratic equation in which Harry lagged due to an error made by him, 2x² - x - 6= 0

<h3><u>To solve</u> - </h3>

➙ the given quadratic equation.

<h3><u>Concept applied</u> - </h3>

➙ We will apply the quadratic formula as given in the question. So, let's study about quadratic equation first because we are supposed to apply the formula in equation.

What is quadratic equation?

➙ A quadratic equation in the variable x is an equation of the form ax² + bx + c = 0, where a, b, c are real numbers, a ≠ 0.

Now, what is quadratic formula?

➙The roots of a quadratic equation ax + bx + c = 0 are given by $\sf{\:\frac{-b \pm\: \sqrt {b ^ 2 - 4ac}}{2a}}$ provided b - 4ac ≥ 0.

<h3><u>Solution</u> - </h3>

here as per the given quadratic equation,

a = 2, b = -1 and c = -6

putting in the formula,

$\implies\sf{x=\frac{-(-1) \pm\: \sqrt {(-1)^2 - 4(2)(-6)}}{2(2)}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {1+48}}{4}}$

$\implies\sf{x=\frac{1 \pm\: \sqrt {49}}{4}}$

$\implies\sf{x=\frac{1 \pm\: 7}{4}}$

Solving one by one,

$\implies\sf{x=\frac{1 + \: 7}{4}}$

$\implies\sf{x=\frac{8}{4}}$

$\implies{\boxed{\bf{x=2}}}$

________________

$\implies\sf{x=\frac{1 - \: 7}{4}}$

$\implies\sf{x=\frac{-6}{4}}$

$\implies{\boxed{\bf{x=\frac{-3}{2}}}}$

________________________________

<em><u>Note</u> - Hey dear user!! You haven't provided the solution which was solved by Harry (A.T.Q). Please go through the solution as it will help you to find the error done by Harry.</em>

Hope it helps!! (:

4 0

2 years ago

LRational or Irrational?<br> 6.12.

katen-ka-za [31]

6.12 is Irrational

3 0

3 years ago

What is the volume of the rectangular prism below? *

horsena [70]

Answer:

Step-by-step explanation: