Uppose a triangle has a,b and c what must be true?
2 answers:
Obtuse: b^2 + c^2 > a^2
Right: b^2 + c^2 = a^2
Acute: b^2 + c^2 < a^2
A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2
So, your Answer would be (B)
Hope this helps!!.!
Obtuse: b^2 + c^2 > a^2
Right: b^2 + c^2 = a^2
Acute: b^2 + c^2 < a^2
A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2
So, your Answer would be (B)
Hope this helps!!.!
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Answer:
5/4
Step-by-step explanation:
There is no ones place after the decimal so 3 is in the tenth place, so 2.4