Uppose a triangle has a,b and c what must be true?

Mathematics

2 answers:

alexdok [17]3 years ago

6 0

Obtuse: b^2 + c^2 > a^2

Right: b^2 + c^2 = a^2

Acute: b^2 + c^2 < a^2

A^2 + B^2 + c^2 - 2bc*cosA
As (A), is an Obtuse cos A is Negative say 2bccosA = - k then;
a^2 = b^2 + c^2 + k
a^2 > b^2 + c^2

So, your Answer would be (B)
Hope this helps!!.!

NeTakaya3 years ago

6 0

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3 years ago

The graph shows the result of a matrix transformation, where the pre-image has dashed lines Which matrix operation is represente

diamong [38]

The matrix operation is the addition subtraction and multiplication involving matrices. The coordinates of the image can be represented as a matrix obtained from the coordinates of the preimage through matrix operations

The best correct option is option D), (the y-coordinate for the point (8, -7) is to be replaced with a 7 to give (7, -7) as follows:

$\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]$

The reason the above matrix value for the matrix operation are correct are as follows:

Known parameters:

From the diagram, we have that the coordinates of the vertices of the preimage are;

(2, -5), (3, -7), (9, -3), and (7, -7)

The coordinates of the vertices of the image are;

(2, 5), (3, 7), (9, 3), and (7, 7)

Required:

The matrix operation for the transformation of the preimage points to the image points

Solution:

The transformation from the coordinates of the vertices of primage to the vertices of image involves the change in the sign from negative to positive, of the y-values of the image, which can be obtained by multiplying by (-1)

Therefore, the required matrix operation is presented as follows:

$\mathbf{\left[\begin{array}{rrrr}1&0\\0&-1\end{array}\right] \left[\begin{array}{rrrr}9&7&3&2\\-3&-7&-7&-5\end{array}\right]} =\left[\begin{array}{rrrr}9&7&3&2\\3&7&7&5\end{array}\right]$