Answer:
904.9 in^3
Step-by-step explanation:
Given data
We are told that the ball is 12 inches in diameter
R= diamter/2= 12/2= 6 in
The volume of a sphere is given as
V= 4/3πr^3
substitute
V= 4/3*3.142*6^3
V= 4/3*3.142*216
V=2714.688/3
V=904.9 in^3
Hence the volume is 904.9 in^3
Answer:
Option (2)
Step-by-step explanation:
Let the equation of the line is,
y - y' = m(x - x')
where (x', y') is a point lying on the given line.
And m = slope of the line = 
Line given in the graph passes through two points (-5, -1) and (-2, -3).
Slope of the line 'm' = 
= 
Therefore, equation of the line passing through(-5, -1) and slope of the line =
will be,
y - (-1) = ![-\frac{2}{3}[x-(-5)]](https://tex.z-dn.net/?f=-%5Cfrac%7B2%7D%7B3%7D%5Bx-%28-5%29%5D)



Option (2) will be the answer.
The answer would be 60. By rounding, 14.2=14; 15.51=16; 14.99=15; 15.8=16.
14+15+16+16=61
Rounding: 61=60
Answer: You would have 50 quarters and 20 dimes
Step-by-step explanation: 50-30=20 so, 20+50=70
The artistic crop isn't helpful; it cuts off some vertex names.
The circumcenter H is the meet of the perpendicular bisectors of the sides, helpfully drawn. We have right triangle ELH, right angle L, so
EH² = HL² + EL²
EL = √(EH² - HL²) = √(5.06²-2.74²) ≈ 4.2539393507665339
Since HL is a perpendicular bisector of EF, we get congruent segments FL=EL.
Answer: 4.25