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mariarad [96]
3 years ago
13

Is 909,756 divisible by 4?

Mathematics
2 answers:
Effectus [21]3 years ago
4 0

Answer

The answer is 227,439

Step-by-step explanation:

yarga [219]3 years ago
3 0

Answer:

I believe this is correct. if so. the answer is yes

Step-by-step explanation:

909756/4= 227439

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14x+10y=72 14x+4y=96 Solve the following system of equations using any method
Anarel [89]
    14x + 10y = 72
    14x +   4y = 96
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                 6       6
                  y = -4
    14x + 10y = 72
14x + 10(-4) = 72
       14x - 40 = 72
             + 40 + 40
              14x = 112
               14      14
                  x = 8
            (x, y) = (8, -4)
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3 years ago
BRAINLIEST ASAP! PLEASE HELP ME :)
marta [7]
<h3>Answer: C) none of the equations are identities</h3>

If you plugged theta = 0 into the first equation, then you would have

sin(45) + cos(45) = sin(0) + cos(0)

sqrt(2) = 1

which is a false equation. We don't have an identity here.

The same story happens with the second equation. Plug in theta = 0 and it becomes

cos(60) - sin(60) = cos^2(0) + tan(0)

1/2 - sqrt(3)/2 = 1 + 0

-0.37 = 1

which is false.

6 0
3 years ago
Josh takes a load of dress shirts to the dry cleaners. The amount he pays for dry cleaning (f) is given by the equation , where
poizon [28]
Sir your probably gunna report this but i have no equation if you could kindly provide the information I requested i would be happy to answer you question
8 0
2 years ago
-4v = -9v + 10 V=<br> Help
Aleksandr-060686 [28]

Answer:

v=2

Step-by-step explanation:

5v=10

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3 0
3 years ago
A NASA spacecraft measures the rate R of at which atmospheric pressure on Mars decreases with altitude. The result at a certain
AysviL [449]

Answer:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

Step-by-step explanation:

For this case we have the following value:

R = 0.0498 \frac{Kpa}{Km}

We can convert this first to \frac{Kpa}{m} like this:

R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}

Now we use the fact the the pressure is defined as P =\frac{F}{A}, whre P is the pressure, F the force and A the area, so then Kpa= \frac{KN}{m^2} and then we can replace this:

R=0.0000498 \frac{KN}{m^3}

Now from definition of work we know that W= Fd where W is the work, F the force and d the distance, so then is equivalent KN =\frac{KJ}{m}

And if we replace this into the equation we got:

R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}

4 0
3 years ago
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