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2 years ago

The equation of the line pass through the points (-4,2) and (-5,2) is

Mathematics

2 answers:

ivanzaharov [21]2 years ago

7 0

Answer:

y = 2

Step-by-step explanation:

Both points are on the horizontal line ...

y = 2

<em>Additional comment</em>

A horizontal line has equation y = constant. A vertical line has equation x = constant.

kramer2 years ago

5 0

<h2><u><em>Answer:</em></u></h2><h2><u><em> y = 2</em></u></h2><h2><u><em>Step-by-step explanation:</em></u></h2><h2><u><em>Both points are on the horizontal line ...</em></u></h2><h2><u><em> y = 2</em></u></h2><h2><u><em>__</em></u></h2><h2><u><em>Additional comment</em></u></h2><h2><u><em>A horizontal line has equation y = constant. A vertical line has equation x = constant.</em></u></h2>

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I need help with this

alexira [117]

Answer:

g(x)=log(x+4)

Step-by-step explanation:

Here the parent function is f(x)=log x. The function has y intercept as 0 at x=1 .

If we observe the translated function we will observe that , the y intercept of new function is 0 at x=-3. Hence the function is moving ahead of the parent function by 4 units and reaches the y intercept being 0.

If we graph

g(X)= log X

the y intercept will be at (1,0)

X = 1 , Y =0

at X=1 , x = -3 or x = X-4

or X=x+4

Hence

new function will be g(x)=log ( x+4)

8 0

3 years ago

What is the answerrrrr to this

Alex_Xolod [135]

Area = 140

16 x 8 = 128

16-12 = 4

(6x4)/2 = 12

128 + 12= 140

8 0

2 years ago

Find the value of the following expression: (2^8 ⋅ 5^−5 ⋅ 19^0)^−2 ⋅ 5 to the power of negative 2 over 2 to the power of 3, whol

koban [17]

Answer:

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

Step-by-step explanation:

$\left(2^8\cdot5^{-5}\cdot19^0\right)^{-2}\cdot\left(\dfrac{5^{-2}}{2^3}\right)^4\cdot228\\\\\text{use}\ a^{-n}=\dfrac{1}{a^n}\ \text{and}\ a^0=1\ \text{and}\ (a^n)^m=a^{nm}\\\\=\left(2^8\cdot\dfrac{1}{5^5}\cdot1\right)^{-2}\cdot\left(\dfrac{\frac{1}{5^2}}{2^3}\right)^4\cdot228=\left(\dfrac{2^8}{5^5}\right)^{-2}\cdot\left(\dfrac{1}{2^35^2}\right)^4\cdot228$

$=\dfrac{(2^8)^{-2}}{(5^5)^{-2}}\cdot\dfrac{1^4}{(2^3)^4(5^2)^4}\cdot228=\dfrac{2^{-16}}{5^{-10}}\cdot\dfrac{1}{2^{12}5^8}\cdot228\\\\\text{use}\ a^n=\dfrac{1}{a^{-n}}\to\dfrac{1}{a^n}=a^{-n}\\\\=2^{-16}\cdot5^{10}\cdot2^{-12}\cdot5^{-8}\cdot228\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=2^{-16+(-12)}\cdot5^{10+(-8)}\cdot228=2^{-28}\cdot5^2\cdot228\\\\=2^{-28}\cdot5^2\cdot4\cdot57=2^{-28}\cdot5^2\cdot2^2\cdot57=2^{-28+2}\cdot5^2\cdot57\\\\=2^{-26}\cdot5^2\cdot57=\dfrac{5^2\cdot57}{2^{26}}$

$\large\boxed{\dfrac{5^2\cdot57}{2^{26}}=\dfrac{1425}{67108864}}$

4 0

2 years ago

Factor the polynomial 8x² − 24x − 224 completely

NeTakaya

Answer:

8(x+4)x(x-7)

Step-by-step explanation:

hope this helps!

3 0

2 years ago

Is finding a car's depreciation over a 10 year period considered as univariate or bivariate?

g100num [7]

Determining a car's depreciation over a ten year period is considered a bivariate.

<h3>What is a bivariate?</h3>

A Bivariate data is made up of two variables that are observed against each other. In determining the deprecation of a car, the cost of the car is observed against the passage of time and the depreciation factor.

To learn more about depreciation, please check: brainly.com/question/25552427

#SPJ1

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2 years ago