Answer:
- x = 0, mult: 3
- x = -4, mult: 2
- x = -5, mult: 2
Step-by-step explanation:
When a polynomial is shown in factored form, its zeros are the values of x that make the factors zero.
The factor x is zero when x=0.
The factor (x+4) is zero when x=-4.
The factor (x+5) is zero when x=-5.
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The multiplicity of a zero is the number of times a given factor is a factor of the polynomial. It is the exponent of the factor.
x = 0 has multiplicity 3.
x = -4 has multiplicity 2.
x = -5 has multiplicity 2.
Answer:
You find the surface area with:
10*2+10*2+4*2+4*2+2*2+2*2+4*7+4*7+4*4+4*4 or in short 152 in^2.
Answer:
Continuously
Step-by-step explanation:
Compounded continuously:
A = Pe^(rt)
A = 11,000 e^(0.0625 × 10)
A = 20,550.71
Compounded semiannually (twice per year):
A = P(1 + r)^t
A = 11,000 (1 + 0.063/2)^(2×10)
A = 11,000 (1 + 0.0315)^20
A = 20,453.96
The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
