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Lapatulllka [165]
3 years ago
6

Casey’s buys a bracelet she pays for the bracelet and pays 0.72 on sales tax the sales tax rate 6%

Mathematics
1 answer:
Sonbull [250]3 years ago
4 0
0.06p = 0.72

p = 12
The original price was $12.

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A national study report indicated that​ 20.9% of Americans were identified as having medical bill financial issues. What if a ne
Alenkasestr [34]

Answer:

The​ p-value for this​ test is 0.22065.

Step-by-step explanation:

We are given that a national study report indicated that​ 20.9% of Americans were identified as having medical bill financial issues.

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<u><em>Let p = proportion of Americans who were identified as having medical bill financial issues in 10 cities.</em></u>

SO, Null Hypothesis, H_0 : p \leq 20.9%   {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is less than or equal to 20.9%}

Alternate Hypothesis, H_A : p > 20.9%   {means that % of Americans who were identified as having medical bill financial issues in these 10 cities is more than 20.9% and is more severe}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 400 Americans from 10 cities who were found having such difficulty =  \frac{90}{400} = 0.225 or 22.5%

            n = sample of Americans = 400

So, <u><em>test statistics</em></u>  =  \frac{0.225-0.209}{{\sqrt{\frac{0.225(1-0.225)}{400} } } } }

                               =  0.77

<u></u>

<u>Now, P-value of the test statistics is given by the following formula;</u>

         P-value = P(Z > 0.77) = 1 - P(Z \leq 0.77)

                                            = 1 - 0.77935 = 0.22065

5 0
3 years ago
What percent of female high school athletes continue their sport as a college (NCAA) student? Use the table below.
nlexa [21]

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Step-by-step explanation:

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3 years ago
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goldenfox [79]

Answer:

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Step-by-step explanation:

Data provided in the question

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3 - 5        0.26

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c. Probability between 3 and 11 phobias is  

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= 0.26 + 0.12  + 0.09

= 0.47

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3 years ago
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