All categories

3 years ago

Need some help on these please!!

Mathematics

1 answer:

Marina86 [1]3 years ago

5 0

i cant help u completely but i like in number 6 that E is 1

You might be interested in

Write a ratio for the situation in three ways, comparing the first quantity to the second quantity. In Largo City, about one in

saul85 [17]

Answer:

Step-by-step explanation:

1/9

(1*4) / (9*4) = 4/36

(1*4) / (9*4) = 5/45

The first one is the ratio as it is stated in the problem.

The second one multiplies top and bottom by 4

The third one multiplies top and bottom of the top ratio by 5.

3 0

3 years ago

I need help due by tomorrow

Flauer [41]

Can you tell me the options first and the formula C=Y

6 0

3 years ago

Read 2 more answers

Leonard made the 3-d shape below for an art project. He wants to paint it blue.

tia_tia [17]

Answer:

90 $cm^{2}$ of blue paint

Step-by-step explanation:

From the given diagram, the sides have the same dimensions and the shape of a triangle.

Area of a triangle = $\frac{1}{2}$ x base x height

Given that, the base of each side = 6 cm, and the height = 10 cm.

Then,

Area of each side of the shape = $\frac{1}{2}$ x 6 x 10

= 30 $cm^{2}$

Since Leonard wish to paint only the 3 sides and not the bottom part of the shape, the amount of paint required can be determined as;

3 x area of each side = 3 x 30

= 90 $cm^{2}$

Leonard would need 90 $cm^{2}$ of paint to paint the sides of the shape.

6 0

3 years ago

How much candy can a human being fit in their mouth?

7nadin3 [17]

I don’t know but a better question is how many cavities do that human being want since they’re tryna see how much candy they can put in their mouth ? :)

8 0

3 years ago

Which of the following is a true polynomial identity?<br>

velikii [3]

Answer:

see below

Step-by-step explanation:

When in doubt, you can always multiply them out to see .

The expression a^6 + b^6 can be treated as the sum of cubes, which factors as ...

p^3 + q^3 = (p +q)(p^2 -pq +q^2)

In this case, you have p=a^2 and q=b^2, so the factorization is ...

a^6 +b^6 = (a^2 +b^2)((a^2)^2 -(a^2)(b^2) +(b^2)^2)

a^6 +b^6 = (a^2 +b^2)(a^4 -a^2b^2 +b^4) . . . . . . matches choice D

The expression a^6 -b^6 can be treated either as the difference of cubes, or as the difference of squares. In the former case, its factorization would be ...

a^6 -b^6 = (a^2 -b^2)(a^4 +a^2b^2 +b^4) . . . . . . matches no offering

In the latter case, its factorization could be any of ...

a^6 -b^6 = (a^3 -b^3)(a^3 +b^3)

a^6 -b^6 = (a^3 -b^3)(a +b)(a^2 -ab +b^2) . . . . . . . . . . . matches no offering

a^6 -b^6 = (a -b)(a^2 +ab +b^2)(a +b)(a^2 -ab +b^2) . . . matches no offering

a^6 -b^6 = (a^2 -b^2)(a^2 +ab +b^2)(a^2 -ab +b^2) . . . matches no offering

8 0

3 years ago