Answer:
D
Step-by-step explanation:
our basic Pythagorean identity is cos²(x) + sin²(x) = 1
we can derive the 2 other using the listed above.
1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)
1 + tan²(x) = sec²(x)
2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)
cot²(x) + 1 = csc²(x)
A. sin^2 theta -1= cos^2 theta
this is false
cos²(x) + sin²(x) = 1
isolating cos²(x)
cos²(x) = 1-sin²(x), not equal to sin²(x)-1
B. Sec^2 theta-tan^2 theta= -1
1 + tan²(x) = sec²(x)
sec²(x)-tan(x) = 1, not -1
false
C. -cos^2 theta-1= sin^2
cos²(x) + sin²(x) = 1
sin²(x) = 1-cos²(x), our 1 is positive not negative, so false
D. Cot^2 theta - csc^2 theta=-1
cot²(x) + 1 = csc²(x)
isolating 1
1 = csc²(x) - cot²(x)
multiplying both sides by -1
-1 = cot²(x) - csc²(x)
TRUE
It would be a cube or a square prism.
Answer:
x= -1
Step-by-step explanation:
Solving through linear equation,
-0.1x + 3/10= 4/10
Bring 3/10 to the other side making it minus
-0.1x = 4/10 - 3/10
-0.1x = (4-3)/10
-0.1x= 1/10
Bring -0.1 to the other side n divide
x= 1/10 ÷ -0.1
( Note that -0.1 is the same as -1/10)
x = 1/10 ÷ -1/10
= 1/10*-10/1
= -10/10
= -1
I think it is b hope it helps
Answer:
20/9
Step-by-step explanation:
2/(9/10)=(2/1)(10/9)=20/9
