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Alekssandra [29.7K]
3 years ago
12

A bookstore had 45 copies of a magazine. Yesterday, it sold 2/3 of them. Today, it sold 1/3 of what remained. How many copies do

es the bookstore have left?
Mathematics
1 answer:
Ket [755]3 years ago
6 0

After the first day, 1/3 of the original amount remained:

... (1/3)·45 = 15


After the second day, 2/3 of that amount remained:

... (2/3)·15 = 10


The bookstore has 10 copies left.

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The function f(x) = 32,000(.723)x models the value of the car after x years. What is the percent change?
Zielflug [23.3K]
.723 is the percentage change, just move the decimal over 2 places. 72.3%
6 0
3 years ago
Mya wants to buy a sweater from a store. The original price of the sweater is $40. The sweater is on sale for 10% off the origin
Nimfa-mama [501]
$36
10% of $40 = $4
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3 0
2 years ago
Which of the following is a solution to the equation "y=3x-1"
nalin [4]

we have

y=3x-1

we know that

If the point is an equation solution, it must satisfy the equation.

<u>case a</u>) (4,1)

Substitute the values of x and y in the equation

1=3*4-1

1=12-1

1\neq11 -------> the point is not solution of the equation

<u>case b</u>) (2,5)

Substitute the values of x and y in the equation

5=3*2-1

5=6-1

5=5 -------> the point is solution of the equation

<u>case c</u>) (4,3)

Substitute the values of x and y in the equation

3=3*4-1

3=12-1

3\neq11 -------> the point is not solution of the equation

<u>case d</u>) (0,-3)

Substitute the values of x and y in the equation

-3=3*0-1

-3\neq-1 -------> the point is not solution of the equation

therefore

<u>the answer is</u>

The point (2,5) is solution of the equation


4 0
3 years ago
Read 2 more answers
What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x = StartFraction neg
Harman [31]

Answer:

x=\frac{-5(+/-)\sqrt{5}} {2}

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

f(x)=x^{2} +5x+5  

equate the function to zero

x^{2} +5x+5=0  

so

a=1\\b=5\\c=5

substitute in the formula

x=\frac{-5(+/-)\sqrt{5^{2}-4(1)(5)}} {2(1)}

x=\frac{-5(+/-)\sqrt{5}} {2}

therefore

x = StartFraction negative 5 plus or minus StartRoot 5 EndRoot Over 2 EndFraction

6 0
3 years ago
Read 2 more answers
11 + 10 × 4 ÷ 5 – 11
Damm [24]

Answer: the answer is 8

Step-by-step explanation: First, you multiply 10 x 4. After that, you divide the answer, 40, by 5. After that you add 11 and then subtract 11, making 11 and 11 cancel out. So the answer is 8.

7 0
3 years ago
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