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Harlamova29_29 [7]
3 years ago
10

Solve the equation .a. 5×=35b. 4× = 18c. 6c–2c = 12.​

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0
A. X=7
b. C= 4.5
c. c=3
gulaghasi [49]3 years ago
5 0

Answer:

a. x=7  b. x= 4.5   c. c= 3

Step-by-step explanation:

a. 5x=35

   5x/5=35/5

     x = 7

b. 4x=18

    4x/4=18/4

     x=4.5

c. 6c-2c=12

   4c = 12

   4c/4 = 12/4

     c=3

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Answer:

\huge \boxed{  \boxed{\mathbb{B)} \frac{40}{6} }}

Step-by-step explanation:

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3 years ago
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oksian1 [2.3K]
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3 0
3 years ago
You need to solve for X
zhenek [66]

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5 0
4 years ago
Log(x⁴+3x³) - log(X + 3 ) + log2 - log6 = 2logx . find the value of x
AfilCa [17]

The given equation is

\begin{gathered} \log (x^4+3x^3)-\log (x+3)+\log 2-\log 6=2\log x \\ \log (\frac{x^4+3x^{3^{}}}{x+3})+\log \frac{2}{6}=\log x^2 \\ \log \frac{x^3(x+3)}{x+3}+\log \frac{1}{3}=\log x^2 \\ \log x^3+\log \frac{1}{3}=\log x^2 \\ \log \frac{x^3}{3}=\log x^2 \\ \frac{x^3}{3}=x^2 \\ x^3-3x^2=0 \\ x^2(x-3)=0 \end{gathered}

hence

x=0\text{ or x=3}

But x cannot be zero so x=3

So the value of x is 3

h

7 0
1 year ago
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