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Anna11 [10]
3 years ago
7

Triangle ABC has the following coordinates: A (-2, 3) B (4, -3) C (-2, -3) What are the coordinates points for triangle A'B'C' i

f the scale factor is −3/4 .
Mathematics
1 answer:
lina2011 [118]3 years ago
7 0

Answer:

A' (3/2, -9/4)

B' (-3, 9/4)

C' (3/2, 9/4)

Step-by-step explanation:

1. You have the following coordinates of the vertices of the triangle ABC:

A (-2, 3) B (4, -3) C (-2, -3)

2. The given scale factor is -3/4, therefore, to calculate the coordinates of the triangle  A'B'C', you must multiply each coordinate of the triangle ABC by the scale factor.

3. Therefore, you obtain that the the coordinates of the triangle  A'B'C' are:

A'=((-2)(-3/4), (3)(-3/4))=(3/2, -9/4)

B'=(4(-3/4), (-3)(-3/4))=(-3, 9/4)

C'=((-2)(-3/4), (-3)(-3/4))=(3/2, 9/4)

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the measure of an angle is (5 x + 10) and the measure of another angle is 55 both angles have a sum of 90 what is the value of x
Bingel [31]

Answer:

x=5

Step-by-step explanation:

5*5=25

25+10=35

35+55=90

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Find each angle measure
Aloiza [94]

It would surely be helpful if you let us know which angles to measure!

4 0
3 years ago
Segu
Lynna [10]

Answer:

The formula is 10 - 3n

Step-by-step explanation:

For an nth term in an arithmetic sequence

U( n ) = a + ( n - 1)d

Where n is the number of terms

a is the first term

d is the common difference

From the sequence above

a = 7

d = 4 - 7 = - 3

The formula for an nth term is

U(n) = 7 + (n - 1)-3

= 7 - 3n + 3

The final answer is

= 10 - 3n

Hope this helps you.

3 0
3 years ago
What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S
Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is y=\frac{1}{3} x+2

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3  

And as the line passing through (-3,1) and is  perpendicular to 3x + y = -8, product of slopes of two line will be -1  as lies are perpendicular.

Let required slope = x  

\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}

So we need to find the equation of a line whose slope is \frac{1}{3} and passing through (-3,1)

Equation of line passing through (x_1 , y_1) and having lope of m is given by

\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)

\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}

Substituting the values we get,

\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}

Hence the required equation of line is found using slope intercept form

4 0
3 years ago
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