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Rus_ich [418]
4 years ago
10

True or false: x/3 is equivalent to 1/3x

Mathematics
1 answer:
Paladinen [302]4 years ago
5 0







1/3x

= (1/3)*x
= (1/3)* (x/1) (because x/1=x)
= (1*x) / (3*1)
= x/3

x/3 is equivalent to 1/3x
~

The statement is true 

hope this helps you
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it cost 3.99 for 25 fl. oz or detergent or 6.99 for 90 fl. oz of detergent which is a better buy? and can you work it out please
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3 years ago
Given the following functions f(x) and g(x), solve (f + g)(5) and select the correct answer below:
Flura [38]

The addition of the function is:

(f+g)(x)= f(x)+g(x)

So, (f+g)(5)= f(5)+g(5)

To find f(5) and g(5), plug in 5 for x in both the functions.

So, f(5)= 8(5)-13 = 40-13 = 27

g(5)= 5-9= -4

Now we can add f(5) and g(5) to get the answer.

So, (f+g)(5)= 27 +(-4) = 27-4= 23

Hence, (f+g)(5)= 23

4 0
4 years ago
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6 0
3 years ago
Astronomers treat the number of stars X in a given volume of space as Poisson random variable. The density of stars in the Milky
cupoosta [38]

Answer:

Explained below.

Step-by-step explanation:

The random variable <em>X</em> is defined as the number of stars in a given volume of space.

X\sim \text{Poisson}\ (\lambda=1)

The probability mass function of <em>X</em> is:

p_{X}(x)=\frac{e^{-\lambda}\lambda^{x}}{x!}

(7)

Compute the probability of exactly two stars in 16 cubic light-years as follows:

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(8)

Compute the probability of three or more stars in 16 cubic light-years as follows:

P(X\geq 3)=1-P(X

(9)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in 4 cubic light years there will be, 4 × (1/16) = (1/4) stars.

(10)

In 16 cubic light years there is only 1 star.

Then in 1 cubic light years there will be, (1/16) stars.

Then in <em>t</em> cubic light years there will be, [<em>t</em> × (1/16)] stars.

7 0
3 years ago
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