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Tpy6a [65]
2 years ago
8

Which expression shows (3*100)+(5*10)+(5*1/10) in standard form?​

Mathematics
1 answer:
Ivenika [448]2 years ago
7 0

Answer:

Step-by-step explanation: 3 x 100 + 4 x 10 + 5 x 1 Standard form is the reverse ...

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10

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no

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A hot-air balloon rises vertically at a constant rate of 8 m/s. A second hot-air balloon moves past the first hot-air balloon at
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The second hot-air balloon is moving 5 m/s

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A standard deck of 52 playing cards contains four of each numbered card 2–10 and four each of aces, kings, queens, and
DerKrebs [107]

Answer:

A standard deck of 52 playing cards contains four of each numbered card 2–10 and four each of aces, kings, queens, and jacks. Two cards are chosen from the deck at random.

Which expression represents the probability of drawing a king and a queen?

StartFraction (4 P 1) (3 P 1) Over 52 P 2 EndFraction

StartFraction (4 C 1) (3 C 1) Over 52 C 2 EndFraction

StartFraction (4 P 1) (4 P 1) Over 52 P 2 EndFraction

StartFraction (4 C 1) (4 C 1) Over 52 C 2 EndFraction

it is D

Step-by-step explanation:

3 0
3 years ago
the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region​
m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

\frac{x}{360} \pi {r}^{2}

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

16 =  \sqrt{10 {}^{2} + 10 {}^{2}   - 2(100) \times  \cos(o) }

This isn't the standard formula, it's for this problem

16 =  \sqrt{200 - 200 \times  \cos(o) }

16 =  \sqrt{200  - 200 \cos(o) }

256 = 200 - 200 \cos(o)

56 =  - 200 \cos(o)

-  \frac{7}{25}  =  \cos(o)

\cos {}^{ - 1} (  - \frac{7}{25} )  =  \cos {}^{ - 1} ( \cos(o) )

106.26 = o

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

\frac{106.26}{360} (100)\pi

\frac{10626}{360} \pi

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

\sqrt{s(s - a)(s - b)(s - c)}

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

\frac{36}{2}  = 18

\sqrt{18(18 - 10)(18 - 10)(18 - 16)}

\sqrt{18(8)(8)(2)}

\sqrt{(36)(64)}

6  \times 8 = 48

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

\frac{10626}{360}  - 48

Which is an approximate or

44.73

6 0
2 years ago
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