The sides of the triangle occur in a ratio of 4 : 7 : 2, so if <em>x</em> is some positive number, then we can write each side's length in terms of <em>x</em> as 4<em>x</em>, 7<em>x</em>, and 2<em>x</em>.
The perimeter is 299 yd, so
4<em>x</em> + 7<em>x</em> + 2<em>x</em> = 299 yd
13<em>x</em> = 299 yd
<em>x</em> = (299 yd) / 13
<em>x</em> = 23 yd
Then the sides of the triangle have lengths of
4<em>x</em> = 4 • 23 yd = 104 yd
7<em>x</em> = 7 • 23 yd = 161 yd
2<em>x</em> = 2 • 23 yd = 46 yd
"Median" here refers to the side length between the shortest and longest sides, so the answer would be 104 yd.
Answer can you show use the graph then i would be able to answer it
<span>The "grey part" is 87
the rest is the "shaded part"
together they add up to the big red rectangle = 128</span>
7. 21.39
8. 6
those are the only two i know
Answer:
C. 40.2°
Step-by-step explanation:
Cosine rule (real handy to remember): c² = a² + b² - 2·a·b·cos(γ)
If you don't know this yet, look it up but in short: c, a and b are the lengths of the sides of the triangle, the angle opposite side a is called α, for b it is β and for c it is γ. That's the convention I've always used anyway, you can call them whatever of course. Anyhow:
c² = a² + b² - 2·a·b·cos(γ)
⇒ |AC|² = |AB|²+|BC|²-2·|AB|·|BC|·cos(∠B)
⇒ |AC|²-|AB|²-|BC|² = -2·|AB|·|BC|·cos(∠B)
⇒ ( |AC|²-|AB|²-|BC|² ) / ( -2·|AB|·|BC| ) = cos(∠B)
⇒ ∠B = arccos( ( |AC|²-|AB|²-|BC|² ) / ( -2·|AB|·|BC| ) )
= arccos( ( 11²-16²-16² ) / ( -2·16·16 ) )
= 40.21101958°
≈ 40.2°
