The figure below shows a shaded region and a nonshaded region. Angles in the figure that appear to be right angles are right ang
les.
Part 1: What is the area, in square feet, of the shaded region?
Part 2: What is the area, in square feet, of the nonshaded region?
PLEASE MAKE SURE THAT IT IS IN SQUARE FEET!!
I KNOW IT'S A LOT OF POINTS, BUT PLEASE DON'T ANSWER IT IF YOU REALLY DON'T KNOW THE ANSWER! IF YOU'RE ANSWER IS CORRECT, AND GREAT, I'LL VOTE THE BRAINLIEST!
PLEASE, I REALLY NEED HELP!!
Part 1: What is the area, in square feet, of the shaded region?
Part 2: What is the area, in square feet, of the nonshaded region?
PLEASE MAKE SURE THAT IT IS IN SQUARE FEET!!
I KNOW IT'S A LOT OF POINTS, BUT PLEASE DON'T ANSWER IT IF YOU REALLY DON'T KNOW THE ANSWER! IF YOU'RE ANSWER IS CORRECT, AND GREAT, I'LL VOTE THE BRAINLIEST!
PLEASE, I REALLY NEED HELP!!
2 answers:
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Answer:
<em>0.5306</em><em>0.5694</em>
Step-by-step explanation:
USing the formuls for calculating the confidence interval for the population proportion;
CI = p±Z*√[p(1-p)/n]
p is the percentage proportion of the population 55%
Z is the z-score at 99% confidence interval = 2.576
n is the sample size = 1079
CI = 0.55 ± 2.576*[0.55(1-0.55)/√1079]
CI = 0.55 ± 2.576*[0.55(0.45)/√1079]
CI = 0.55 ± 2.576*[0.2475/√1079]
CI = 0.55 ± 2.576*[0.2475/32.85]
CI = 0.55 ± 2.576*[0.00753]
CI = 0.55 ±0.0194
CI =(0.55-0.0194, 0.55+0.0194)
CI = (0.5306, 0.5694)
<em>Hence, a 99% confidence interval of the proportion of the population that will support such a law is 0.5306</em><em>0.5694</em>