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What is the precision measurement of 80 inches?

lawyer [7]

The precision is 10 inches. This is because the 0 at the end of the number is not considered a significant digit in the form in which the number is written, and hence "80 inches" is to be considered a roundoff from a number which can be from 75-85 inches.

3 0

3 years ago

If the vertices of triangle bcd are b(-3,3), c(3,5), and d(-1,0), what is the perimeter

zloy xaker [14]

Distance formlula
D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

when you want to find the distance between points (x1,y1) and (x2,y2)

we nee
distace from
b to c
c to d
d to b

b to c is (-3,3) to (3,5)
D= $\sqrt{(3-(-3))^{2}+(5-3)^{2}}$ =2√10

c to d is (3,5) to (-1,0)
D= $\sqrt{(-1-3)^{2}+(0-5)^{2}}$ =√41

d to b is (-1,0) to (-3,3)
D= $\sqrt{(-3-(-1))^{2}+(3-0)^{2}}$ =√13

add

b to c+c to d+d to b=2√10+√41+√13

perimiter=2√10+√41+√13 units

7 0

3 years ago

Pensacola, Florida , gets an average of 64.28inches of precipitation per year. Key West , Florida, gets an average of 38.94 inch

svp [43]

Answer: 25.34 inches of precipitation

Step-by-step explanation: you have to subtract the precipitation from pensacola by the precipitation from Key West. so when you subtract the 2 you get 25.34 inches

6 0

3 years ago

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Becky drew a scale drawing of a sign before creating it. Her scale drawing had a width of 6 inches, and the actual sign has a wi

stealth61 [152]

Answer:

$4ft *\frac{12in}{1 ft}= 48 in$

Now since we have the same units for the scale model and the real one we can find the scale factor like this:

$Scale = \frac{48 in}{6in}= 8$

And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model

Step-by-step explanation:

For this problem we know that the scale model had a widthof 6 inches. And the actual model has a width of 4ft. First we need to convert the 4ft to inches and we got:

$4ft *\frac{12in}{1 ft}= 48 in$

Now since we have the same units for the scale model and the real one we can find the scale factor like this:

$Scale = \frac{48 in}{6in}= 8$

And we can conclude that the scale factor is 1:8 and that represent that the real object is 8 times larger than the scale model

6 0

3 years ago

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→[infinity]

Fynjy0 [20]

Answer:

$\lim_{x\rightarrow \infty}(\frac{5x-3}{5x+2})^{5x+1}=e^{-5}$