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aleksandrvk [35]
4 years ago
13

How do the functions compare over the interval 0 ≤ x ≤ 1​

Mathematics
1 answer:
Zarrin [17]4 years ago
5 0

Answer:

The exponential grows at approximately four times the rate of the quadratic.

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What is 18 out of 720 ? <br> Write as a percent . <br> Round to the nearest tenth
nika2105 [10]

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18/720 =2.5% that is the answer

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A survey of 270 young professionals found that one dash eighth of them use their cell phones primarily for​ e-mail. Can you conc
IceJOKER [234]

Answer:

As 0.17 is below the upper limit of the confidence​ interval, so we can conclude that the population proportion is less than 0.17.

Step-by-step explanation:

We are given that a survey of 270 young professionals found that one dash eighth of them use their cell phones primarily for​ e-mail.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

                            P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of people who use their cell phones primarily for​ e-mail =  \frac{1}{8} = 0.125

           n = sample of young professionals = 270

           p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                   of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

        = [ 0.125-1.96 \times {\sqrt{\frac{0.125(1-0.125)}{270} } } , 0.125+1.96 \times {\sqrt{\frac{0.125(1-0.125)}{270} } } ]

        = [0.08 , 0.16]

Therefore, 95% confidence interval for the population proportion who use cell phones primarily for​ e-mail is [0.08 , 0.16].

Since, the above confidence interval have values which is less than 0.17; so we conclude that the population proportion is less than 0.17.

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2 haha

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