Answer:
503 $1 tickets sold.
Step-by-step explanation:
Use two equations
Let x = number of $1 tickets sold
Let y = number of $1.50 tickets sold
x + y = 739
1x + (1.5)y = 857
First equation ==> y = 739 - x
Plug this into the second equation
x + (1.5)(739 - x) = 857
x + 1108.5 - 1.5x = 857
- 0.5x = -251.5
x = 503
There were 503 $1 tickets sold.
To find the number of $1.50 tickets, just plug this value of x into either one of the equations.
(503) + y = 739 (739 - 503 = 236)
y = 236
There were 236 $1.50 tickets sold.
Answer:
B
Step-by-step explanation:
This is the correct answer because the difference between 32 and 29 is 3 and the intial price is 32, Hence 3/32 (100)
Answer:
pit it on -4 because your reflecting it on x
is this the full question?
<h3>
Answer: H. 33</h3>
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Work Shown:
Solve 5m^2 = 45 for m to get
5m^2 = 45
m^2 = 45/5
m^2 = 9
m = sqrt(9)
m = 3
I'm making m to be positive so that way the expression 12m is not negative. Otherwise, sqrt(12m) would not be a real number result.
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Plug m = 3 into the expression we want to evaluate
m^3 + sqrt(12m)
3^3 + sqrt(12*3)
27 + sqrt(36)
27 + 6
33
