To answer the question, all you need to do is figure out at what value of stickers would the remaining stickers be equal to 2 if the piles are made up of either 3 to a set or 4 to a set. To do this, we need to figure out the size of the whole set of stickers.

Lets assume that the total number of stickers is 14. Lets test the 2 given conditions. If we divide it in piles of 3 then we will have a pile of 12 stickers (4 piles of 3 stickers each) with 2 stickers remaining.

Lets test the second condition. If we divide it in piles of 4, we will again have 12 stickers (3 piles of 4 stickers each) with 2 stickers remaining.

Now that both conditions have been satisfied, all we have to do is see how many stickers are left if we make a pile of 12 stickers. In this case, we will have just one pile of 12 stickers and, again, we will be left with 2 stickers.

Therefore, the answer is 2 stickers

6 0

3 years ago

Rank the vector combinations on the basis of their angle, measured counterclockwise from the positive x axis. vectors parallel t

Charra [1.4K]

The correct answer for this question is this one:


1- have an angle of 0∘ .
2- vectors parallel to the positive x axis
3- all angle measures fall between 0∘ and 360∘.
Hope this helps answer your question and have a nice day ahead.

8 0

4 years ago

114

liq [111]

Line q has slope 3, as you've found.

Any line perpendicular to q will then have slope -1/3, as you've found.

Line p thus has slope -1/3 and we know it passes through (6, -5), so from the point-slope formula we get the equation

$y - (-5) = -\dfrac13 (x - 6) \implies \boxed{y + 5 = -\dfrac13 (x - 6)}$

3 0

2 years ago