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Annette [7]
3 years ago
11

The doubling time of a population of grasshoppers is 10 days. By what factor does the population of grasshoppers grow in 35 days

?
Mathematics
2 answers:
12345 [234]3 years ago
8 0
So in 10 days the grasshopper (x) is doubled (2x)
20 days it is 2(2x) or 4x
30 days it is 2(4x) or 8x
in 35 days it is 1/2 of 10 so 1/2 times 2 times 8x=8x

it increased by a factor of 8
Zolol [24]3 years ago
4 0

The <em>correct answer</em> is:

11.3

Explanation:

In 10 days, the population x would double, becoming 2x.

Every 10 days after, the population would double again. This means at 20 days, the population would be 2(2x) = 4x, and at 30 days, the population would be 2(4x) = 2(2(2x)) = 8x.

Writing the repeated multiplication out, we see that this can be represented with exponents. 10 days would be 2¹(x); 20 days would be 2²(x); 30 days would be 2³(x).

5 days would not be adding a whole number to the exponent, as it is only half of the time it takes to double. This means we would add 0.5 to the exponent; this would make 35 days

2^{3.5}(x), which comes out to 11.3x. This means it increases by a factor of 11.3 in 35 days.

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Answer:

\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

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<u>Calculus</u>

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  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (cu)' = cu'

Derivative Property [Addition/Subtraction]:
\displaystyle (u + v)' = u' + v'
Derivative Rule [Basic Power Rule]:

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Integration

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Integration Rule [Reverse Power Rule]:
\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:
\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution/u-solve</em>.

  1. Set <em>u</em>:
    \displaystyle u = 4 - x^2
  2. [<em>u</em>] Differentiate [Derivative Rules and Properties]:
    \displaystyle du = -2x \ dx
  3. [<em>du</em>] Rewrite [U-Solve]:
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<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Apply U-Solve:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du
  2. [Integrand] Simplify:
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    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du
  4. [Integral] Apply Integration Rule [Reverse Power Rule]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C
  5. [<em>u</em>] Back-substitute:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.

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Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

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Topic: AP Calculus AB/BC (Calculus I/I + II)

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