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Soloha48 [4]
4 years ago
14

Whats the area of a rectangle with the width of 11cm and length of 3cm

Mathematics
1 answer:
Anettt [7]4 years ago
7 0
Area=length times width=11cm times 3cm=33 square cm or 33 \space\ cm^2
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dimulka [17.4K]
If that is a decimal the 1 would be in the tenths. If it is a whole number it would be in the hundred thousands
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3 years ago
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(-0.4)^2 sum pls i need this by tonight i have to finish my math corrections pls
netineya [11]

Answer:

(-0.4)²

= -0.4×-0.4

product of two negative numbers is positive

so, 0.4×0.4

=4/10×4/10

=16/100

=0.16

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5C%7B%20%5Cfrac%20%7B%20%28%20%5Csqrt%20%7B%203%20%7D%20%29%20%5Ctimes%203%20%5E%20%7B%20-%20
ZanzabumX [31]

Answer:

Step-by-step explanation:

Exponent law:

    \sf \bf a^m * a^n = a^{m+n}\\\\ (a^m)^n = a^{m*n}

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       First convert radical form to exponent form and then apply exponent law.

 \sf \sqrt{3}=3^{\frac{1}{2}}\\\\\sqrt{5}=5^{\frac{1}{2}}

\sf \left(\dfrac{(\sqrt{3}*3^{-2}}{(\sqrt{5})^2}\right)^{\frac{1}{2}}= \left(\dfrac{3^{\frac{1}{2}}*3^{-2}}{(5^{\frac{1}{2}})^2} \right )^{\frac{1}{2}}

                      = \left(\dfrac{3^{\frac{1}{2}-2}}{5^{\frac{1}{2}*2}}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{1-4}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\left(\dfrac{3^{\frac{-3}{2}}}{5}\right)^{\frac{1}{2}}\\\\=\dfrac{3^{\frac{-3}{2}*{\frac{1}{2}}}}{5^{\frac{1}{2}}}\\\\ =\dfrac{3^{{\frac{-3}{4}}}}{5^{\frac{1}{2}}}

3 0
2 years ago
El administrador de una cafetería sabe que vende diariamente 50 litros de jugo mixto. Para elaborar este jugo se emplean dos pre
Nina [5.8K]

Answer:

Se necesitan 37.5 litros del preparado que contiene 5% de jugo natural, y 12.5 litros del que contiene 25%.

Step-by-step explanation:

Primero calculamos la cantidad total de jugo natural que se necesita, a partir del volumen de jugo mixto que se quiere vender:

  • 50 L * 10/100 = 5 L

Ahora, que X sean los litros del preparado con jugo de 5%, y que Y sean los litros del preparado con jugo de 25%:

La suma de ambos preparados tiene que ser 50 L:

1.    x + y = 50

La suma del jugo natural tiene que ser 5:

2.   x*5/100 + y*25/100 = 5

Por lo que tenemos <em>un sistema de dos ecuaciones y dos incognitas</em>.

Expresamos x en términos de y:

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Reemplazamos x en la segunda ecuación:

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Y despejamos <em>y</em>:

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Usando ese valor de y, calculamos x:

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3 years ago
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dlinn [17]

Answer:

5 x 4 + 2 - 3 / 1

Step-by-step explanation:

This took me so much tries to do but got it. Hope it helps! :)

5 0
4 years ago
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