Question

An alloy of tin is 14% tin and weighs 22 pounds. A second alloy is 9% tin. How much of the second alloy must be added to the first alloy to get a 12% mixture. 7.33 7.7 11 14.67

Answer 1

I believe the answer would be 14.67 someone let me know 

Answer 2

Answer: 14.67 pounds of second alloy must be added to the first alloy to get 12% mixture.

Step-by-step explanation:

Since we have given that

A alloy of 14% tin weigh 22 pounds.

There is a  second alloy of 9% tin .

we need to find the quantity of second alloy that must be added to first alloy get a 12% mixture.

We will use "Mixture Alligation":

   Ist alloy   IInd alloy

     14%             9%

               12%

-------------------------------------

 12-9          :             14-12

    3            :                2

Since Ist alloy = 22 pounds

According to question, it becomes,

$\frac{3}{2}=\frac{22}{x}\\\\2\times 22=3x\\\\44=3x\\\\\frac{44}{3}=x\\\\14.67=x$

Hence, 14.67 pounds of second alloy must be added to the first alloy to get 12% mixture.