Answer:
-x^4y + x
Step-by-step explanation:
-2x^7y^2 + 2x^4y + 2x^3y
You can take out 2x^3y because there is enough of that in each part of the equation. Then you just divide the whole numbers and subtract the exponents.
-x^4y + x
First you input the equation into the quadratic formula:
__________
x=<span><span><span>−<span>(<span>−2</span>)</span></span>±<span>√<span><span><span>(<span>−2</span>)</span>2</span>−<span><span>4<span>(1)</span></span><span>(5)</span></span></span></span></span>
</span> -----------------------------
2(1)
Next you simplify the formula:
___
x=<span><span>2±<span>√<span>−16
</span></span></span></span> ------------
2
This problem has no real solutions.
Ok,
The total is 63$:
= 63
It shows us one of the numbers for the equation, 13
+ 13 = 63
Two passes together plus the thirteen equals the total of 63$
the price of the pass is unknown, so we can use a variable to figure it out:
2x + 13 = 63
Now we solve
First subtract 13 from both sides:
2x + 13 - 13 = 63 - 13
Then divide both sides by 2:
2x ÷ 2 = 50 ÷ 2
Now we get our answer:
x = 25
Answer:91 i think
Step-by-step explanation:
