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polet [3.4K]
3 years ago
7

Rita earned 45 points on a test. She lost 8 points , earned 53 points , then lost 6 more points. What is Rita's final score on t

he test
Mathematics
2 answers:
Elodia [21]3 years ago
7 0
Loss is negative
earned is plus
45
lost 8
45-8=37
eaned 53
37+53=90
lost 6
90-6=84

final score is 84 points
maxonik [38]3 years ago
5 0
Rita's final score is 84 .

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For the school play,adult tickets cost $4 and children tickets cost $2. Natalie is working at the tickets counter just sold $20
Lisa [10]
Adult tickets = A
Children tickets = C

A×4. C×2

A×3. C×4

A×2. C×6

A×1. C×8
5 0
3 years ago
Find the area of a circle circumscribed about an equilateral triangle whose side is 18 inches long. 81 108 243
jekas [21]

Answer:

Area=339.2920in^2 \ or \ 108\pi \ in^2

Step-by-step explanation:

Area of circle is given as:

A=\pi\ r^2

Where r=radius

To find radius of a circle circumscribing an equilateral triangle, we use the expression

r=\frac{a\sqrt3}{3}

Where, a is the length of sides of the equilateral triangle. Therefore:-r=\frac{18\sqrt3}{3}\\r=6\sqrt3 \ or \ 10.3923in

We can then proceed and calculate the area of the circle as follows:-

A=\pi\ r^2\\A=\pi(10.3923)^{2}\\A=339.29\ or \ 108\pi

*The attached picture illustrates what the circumscribed equilateral triangle looks like

4 0
4 years ago
What is the rate of change?
eduard

Answer:

12

Step-by-step explanation:

12 +30= 42

42+12=54

4 0
3 years ago
The width of the rectangle is 2 more than the length. The area of the rectangle is 63 square inches. How long is the width?
wariber [46]

Answer:

9 inches

Step-by-step explanation:

Area of rectangle= length ×width

Let the length of the rectangle be x inches.

Width of rectangle= (x +2) inches

<em>since</em><em> </em><em>the</em><em> </em><em>width</em><em> </em><em>is</em><em> </em><em>2</em><em> </em><em>more</em><em> </em><em>than</em><em> </em><em>the</em><em> </em><em>length</em><em>.</em>

63= x(x+2)

63= x(x) +2x

<em>Bringing</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em>,</em>

x² +2x -63= 0

(x +9)(x-7) = 0 (<em>factorise</em><em>)</em>

x+9= 0 or x-7= 0

x= -9 or x= 7

(reject)

width of rectangle

= 7+2

= 9 inches

*We reject x= -9 since the length of the rectangle cannot be a negative number.

4 0
4 years ago
The strength of a certain type of rubber is tested by subjecting pieces of the rubber to an abrasion test. For the rubber to be
My name is Ann [436]

Answer:

Step-by-step explanation:

Hello!

You have the hypothesis that the average weight loss for rubber after an abrasion test is less than 3.5 mg. To test this a large sample of pieces of rubber were sampled and subjected to the abrasion test.

With the given information you must test whether the researcher's hypothesis is sustained or not.

The study variable is,

X: Weight loss of rubber cured in a certain way after being subjected to the abrasion test. (mg)

There is no information about the variable distribution, but since it is said that the sample is a "large number" I'll take it as if it is bigger than 30 and apply the Central Limit Theorem to use the approximation of the sample mean to normal. This way I can use the Z-statistic for the test.

Symbolically the statistic hypothesis is:

H₀: μ ≥ 3.5

H₁: μ < 3.5

α: 0.05 (since is not listed, I'll choose one of the most common signification levels)

You have a one-tailed critical region, this means the p-value will also be one-tailed to the left of the distribution (i.e. →-∞)

The formula of the statistic is:

Z= <u> X[bar] - μ </u> ≈ N(0;1)

        δ/√n

To calculate the statistic you have to use the information given.

The sample mean X[bar]= 3.4 mg

Upper bond of 95% CI= 3.45 mg

The basic structure of a CI for the mean is

"estimator" ± "margin of error"

Upper bound is "estimator" + "margin of error"

Using the formula:

Ub= X[bar] + d ⇒ 3.45= 3.4 + d

⇒ d= 3.45 - 3.4 = 0.05

Where d is the margin of error

d= Z_{1-\alpha /2} * (δ/√n)

d= Z_{0.975} * (δ/√n)

d/Z_{0.975}= (δ/√n)

(δ/√n)= 0.05/ 1.96 = 0.0255

(δ/√n) is the denominator in the formula, corresponds to the standard deviation of the distribution.

Now you have all values and can calculate the statistic under the null hypothesis:

Z= <u> 3.4 - 3.5 </u> = -3.92

       0.0255

And the p-value:

P(Z ≤ -3.92) = 0.000044 ⇒ My Z- table goes up to P(Z ≤ -3.00) = 0.001, so using strictly the table I can say that the probability is less than 0.001.

To calculate the exact probability I've used a statistic program.

p-value < 0.001

I hope it helps!

8 0
3 years ago
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