All categories

2 years ago

(10 points)I REALLY NEED HELP NOW!! (A) positive (b)negative (c)zero

Mathematics

2 answers:

tatyana61 [14]2 years ago

8 0

Hello from MrBillDoesMath!

Answer:

Cchoice B is the correct answer.

Discussion:

As stated by an earlier respondent, choice B is the correct answer. But why?

From the diagram, point B lies between 0 and 1 which means B is positive

From the diagram, point C lies between -1 and -2 which means C is negative

The quotient of a negative number by a positive number is negative, giving the answer as choice c

Regards,

MrB

P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!

Sindrei [870]2 years ago

4 0

The answer is B because b is positive and C is negative so if you divide it you will get a negative answer

You might be interested in

Suppose A= {5,6,8,10,12} and B= {8,9,12,13,14} <br><br><br><br> What is AunionB?

earnstyle [38]

Answer:

A ∪ B = {5 , 6 , 8 , 9 , 10 , 12 , 13 , 14}

Step-by-step explanation:

The symbol of union is ∪

The symbol of intersection is ∩

In the sets A and B

A ∪ B means all elements in sets A and B without repeating

A ∩ B means the common elements in sets A and B

n(A ∪ B) = n(A) + n(B) - n(A ∩B), where n is the number of elements in the set

Now let us solve the question

∵ Set A = {5 , 6 , 8 , 10 , 12}

∴ n(A) = 5

∵ Set B = {8 , 9 , 12 , 13 , 14}

∴ n(B) = 5

The elements 8 and 12 are in the two sets

∵ There are two common elements in the two sets 8 and 12

∴ n(A ∩ B) = 2

Use the 3rd rule above to find how many elements in A ∪ B

∵ n(A ∪ B) = 5 + 5 - 2

∴ n(A ∪ B) = 8

∴ The set of A ∪ B has 8 elements

∵ A ∪ B means all elements in A and B without repeating

∴ A ∪ B = {5 , 6 , 8 , 9 , 10 , 12 , 13 , 14}

4 0

3 years ago

5z+7=3 what solution

Maru [420]

Answer:

z = -4/5

Step-by-step explanation:

5z + 7 = 3

5z = -7 + 3

5z = -4

z = -4/5

Hope this helps :)

Let me know if there are any mistakes!!

6 0

3 years ago

Suppose you are given either a fair dice or an unfair dice (6-sided). You have no basis for considering either dice more likely

hoa [83]

Answer: Our required probability is 0.83.

Step-by-step explanation:

Since we have given that

Number of dices = 2

Number of fair dice = 1

Probability of getting a fair dice P(E₁) = $\dfrac{1}{2}$

Number of unfair dice = 1

Probability of getting a unfair dice P(E₂) = $\dfrac{1}{2}$

Probability of getting a 3 for the fair dice P(A|E₁)= $\dfrac{1}{6}$

Probability of getting a 3 for the unfair dice P(A|E₂) = $\dfrac{1}{3}$

So, we need to find the probability that the die he rolled is fair given that the outcome is 3.

So, we will use "Bayes theorem":

$P(E_1|A)=\dfrac{P(E_1)P(A|E_1)}{P(E_1)P(A|E_1)+P(E_2)P(A|E_2)}\\\\(E_1|A)=\dfrac{0.5\times 0.16}{0.5\times 0.16+0.5\times 0.34}\\\\P(E_1|A)=0.83$

Hence, our required probability is 0.83.

8 0

3 years ago

-2x3x simplify please

Anvisha [2.4K]

-6x is the answer hope it helps

4 0

3 years ago

The plans for a shed call for a rectangular floor with a perimeter of 276 ft. the length is two times the width. find the length

hichkok12 [17]

2l+2w=276
l=2w

2(2w)+2w=276
6w=276
w=46
l=92

6 0

2 years ago