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Debora [2.8K]
2 years ago
7

(10 points)I REALLY NEED HELP NOW!! (A) positive (b)negative (c)zero

Mathematics
2 answers:
tatyana61 [14]2 years ago
8 0

Hello from MrBillDoesMath!

Answer:

Cchoice B is the correct answer.

Discussion:

As stated by an earlier respondent, choice B is the correct answer. But why?

From the diagram, point B lies between  0 and 1 which means B is positive

From the diagram, point C lies between  -1 and -2 which means C is negative

The quotient of a negative number by a positive number is negative, giving the answer as choice c


Regards,  

MrB

P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


Sindrei [870]2 years ago
4 0
The answer is B because b is positive and C is negative so if you divide it you will get a negative answer
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Graham paid $87.45 for a pair of jeans. This amount included a tax of 40%. What was the cost of the jeans before tax?
kiruha [24]

The final price is the cost plus the tax.

Since we know the tax and a percent, we can write this as

T = C(1+r)

T = what Graham paid = $87.45

C = cost before tax

r = tax rate expressed as a decimal = .40

Plugging in what we know

87.45 = C (1+.4)

87.45 = C(1.4)

Divide both sides by 1.4

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3 years ago
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sveta [45]

2 hrs and 12 min or 2.2 hrs

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3 years ago
Rewrite this division expression a an equivalent multiplication expression: 5/8 divided by 2/3
Ulleksa [173]

Answer:

Step-by-step explanation:

Dividing by a fraction is the same as multiplying by the upside-down fraction.

(5/8) ÷ (2/3) = (5/8) ⋅ (3/2) = 15/16

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3 years ago
Y=x^2-6x-16 in vertex form
satela [25.4K]

Answer:

y=(x-3)^{2} -25

Step-by-step explanation:

The standard form of a quadratic equation is y=ax^{2} +bx+c

The vertex form of a quadratic equation is y=a(x-h)^{2} +k

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

h=\frac{-b}{2a}

In this case, our quadratic equation is y=x^{2} -6x-16. Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

h=\frac{-b}{2a} ⇒ h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is y=x^{2} -6x-16

y=x^{2} -6x-16 ⇒ y=(3)^{2} -6(3)-16 ⇒ y=9-18-16 ⇒ y=-25

This y-value that we just found is our k-value.

Next, we are going to set up our equation in vertex form. As a reminder, vertex form is: y=a(x-h)^{2} +k

a: 1

h: 3

k: -25

y=(x-3)^{2} -25

Hope this helps!

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