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4 years ago

Please help, its urgent

Mathematics

1 answer:

Verdich [7]4 years ago

8 0

Step-by-step explanation:

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Set up a linear system and solve.

liubo4ka [24]

Answer:

The two integers are 23 and 12

Step-by-step explanation:

Let the two integers be f and g

Let f be the biggest and g the smallest integer

From the first statement, the sum of the two integers is 35 i.e

f + g = 35. (1)

From second statement, we were told that when the smaller integer is subtracted from twice the larger, the result is 34 i.e

2f — g = 34. (2)

Now we'll solve by elimination method as follows:

Add equation (2) and (1) together:

2f — g = 34

+ f + g = 35

3f = 69

Divide both side by the coefficient of f i.e 3

f = 69/3

f = 23

Substituting the value of f into equation(1)

f + g = 35

23 + g = 35

Collect like terms

g = 35 — 23

g = 12

The two integers are 23 and 12

4 0

3 years ago

Use compatible numbers to estimate 5 × 1,021

BigorU [14]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

5/9 , 4/15 ,dan 3/5

vichka [17]

4/15, 5/9 and 3/5.

Hope this helps! :)

5 0

3 years ago

I do you get the answers????

telo118 [61]

Research is the way people get their answers most of the time

3 0

4 years ago

The accompanying frequency distribution represents the square footage of a random sample of 500 houses that are owner occupied y

ioda

Answer:

$\bar X = \frac{\sum x_i f_i}{n} = \frac{1220750}{500}=2441.5$

$s^2= \frac{3408029125 -\frac{(1220750)^2}{500}}{500-1} =856849.7$

$s= \sqrt{856849.7}=925.662$

Step-by-step explanation:

For this case we can create the following table

Interval Frequency (f) Midpoint(xi) xi *f xi^2* f

0-499 9 249.5 2245.5 560252.3

500-999 13 749.5 9743.5 7302753

1000-1499 33 1249.5 41233.5 51521258.25

1500-1999 115 1749.5 201193.5 361986278.8

2000-2499 125 2249.5 281187.5 632531281.3

2500-2999 81 2749.5 222709.5 612339770.3

3000-3499 47 3249.5 152726.5 496284761.8

3500-3999 45 3749.5 168727.5 632643761.3

4000-4499 22 4249.5 93489 397281505.5

4500-4999 10 4749.5 47495 225577502.5

Total 500 1220750 3408029125

$\sum f_i = 500 , \sum x_i f_i = 1220750, \sum x^2_i f_i = 3408029125$

For this case we can calculate the sample mean with this formula:

$\bar X = \frac{\sum x_i f_i}{n} = \frac{1220750}{500}=2441.5$

And for the sample variance we can use the following formula:

$s^2= \frac{\sum x^2_i f_i - \frac{(\sum x_i f_i)^2}{n}}{n-1}$

And if we replace we got:

$s^2= \frac{3408029125 -\frac{(1220750)^2}{500}}{500-1} =856849.7$

And the deviation is just the square root of the sample variance and for this case is:

$s= \sqrt{856849.7}=925.662$

4 0

3 years ago