The expression would add 6d+7 and 10d+10.
So…
6d+7+10d+10
We add like terms which would be (7 and 10) and (6d and 10d)
7+10 is 17
6d+10d is 16d
So the answer would be
16d +17
The formula for a rectangle's perimeter is
P = 2l + 2w
We know the length is 2 ft greater than thrice the width, so 2l becomes:
3w + 2ft + 3w + 2ft
Substitute.
P = 3w + 2ft + 3w + 2ft + 2w
Add like terms.
P = 8w + 4ft
Substitute P.
84 ft = 8w + 4ft
Subtract 4 ft from both sides to eliminate. (Property of equality)
84 ft - 4ft = 8w + 4ft - 4ft
80 ft = 8w
Divide 8 on both sides to isolate w.
80 ft / 8 = 8w / 8
10 ft = w
We have the value of w, now look for the l which we know is 2 feet more than thrice the value of w.
l = 10 ft × 3 + 2 ft
l = 30 ft + 2 ft
l = 32 ft
Therefore, the length and the width of the rectangle is 10 ft (w) and 32 ft (l).
Check:
84 ft = (2) (10 ft) + (2) (32 ft)
84 ft = 20 ft + 64 ft
84 ft = 84 ft ✔
♧
A. (x+8)^ 2 + 1
B. (x-3)^ 2 - 8
C. ( x - 3/2) ^ 2 - 1/4