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crimeas [40]
4 years ago
5

The three sides of a triangle are n, 4n−8, and 2n+8. If the perimeter of the triangle is 63 feet, what is the length of each sid

e?
Mathematics
2 answers:
iren2701 [21]4 years ago
8 0

Answer:

9,28,36

Step-by-step explanation:

The perimeter of a triangle is the 3 sides added up. We know the 3 sides, and we know that the perimeter equals 63.Therefore,

n+4n-8+2n+8=63

Now, we need to solve for n. To do this, we need to get n by itself.

Combine like terms by adding all the variables together, and all the numbers together

(n+4n+2n)+(-8+8)=63

7n=63

Since n is being multiplied by 7, divide both sides by 7. This will cancel out the 7, and leave n by itself

7n/7=63/7

n=9

Now we know n, and can substitute it into the sides and find the lengths

n

9

4n-8

4(9)-8

36-8

28

2n+8

2(9)+8

18+8

26

So, the side lengths are 9, 28 and 36

MrRissso [65]4 years ago
5 0

Find <em>n</em> :

P = a + b + c

63 = n + (4n - 8) + (2n + 8)

63 = (n + 4n + 2n) + (-8 + 8)

63 = 7n

n = 63 ÷ 7

n = 9

Sides :

1.) n = <u>9</u>

2.) 4n - 8 = 4(9) - 8 = 36 - 8 = <u>2</u><u>8</u>

3.) 2n + 8 = 2(9) + 8 = 18 + 8 = <u>2</u><u>6</u>

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

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