There are standard formulas for this type of problem. However, it can also be solved by a combination of simple steps.
First, the shortest distance from the point (3,5) to the line y = x +4 (line1) will be along a straight line perpendicular to line1. Give the perpendicular line the name line2. Since the slope of line1 is 1, the slope of line2 will be -1.
Second, since line2 must go through (3,5) and also have a slope of -1, the point slope form can be used for line2:
y - 5 = (-1) (x -3)
So the equation of line2 is y = -x +8.
Third, the point of intersection of line1 and line2 can be found by solving the set of equations:
y = x +4
y = -x + 8
The solution of this set of two equations is x = 2, y = 6 i.e. the point (2,6) .
Fourth, the distance formula can be used to find the distance between (3,5) and (2,6)
d = sqrt( (3-2)2 + (5-6)2 ) = sqrt(2)
This is the desired distance.
Their daily rate is
miles per day
Using distance-speed-time formula, we can calculate the time
days
They need 21-3=18 more days to finish the trip
The vertex is at (2, 5).
To find the vertex, we first find the axis of symmetry; this is given by
x = -b/2a
For our equation, b = -16 and a = 4:
x = -(-16)/2(4) = 16/8 = 2
We substitute this back into our equation:
y = 4(2)² - 16(2) + 21 = 4(4) - 32 + 21 = 5
Therefore the vertex is at (2, 5).
Answer:
QUESTION:
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ANSWER:
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A A equation that’s perpindicular to y = 4x - 1 and passes through the point (2, -9) is…
Answer: y = -3/4x - 15/2
Explanation: Opposite reciprocal slopes and plug in -9 with y and 2 with x then solve for b
-9 = -1.5 + x
x = -15/2
