Answer:
Friday night.
Less expensive.
Step-by-step explanation:
Cost of 1 ticket on Friday = 48/3 = $16.
Cost on Saturday = 36 / 2 = $18.
Now 96 / 6 = $16 so the brother and his friends will have to go to the Friday concert. From the above costs we see that they did buy the less expensive ticket.
Answer:
540 mm
Step-by-step explanation:
Here we are given a rectangular box with dimensions of the top surface as 40 mm and 230 mm
We are asked to determine the measurement of the ribbon which may go all the way around the edge of it. Basically we are being asked the perimeter of the top surface. The perimeter is given as the
P=2 (l+w)
l = 230
w = 40
P=2(230+40)
P=2 x 270
P= 540
Hence we need 540 mm of ribbon to go all the way around the edge of the top of the box.
Answer:
sin(2x)=cos(π2−2x)
So:
cos(π2−2x)=cos(3x)
Now we know that cos(x)=cos(±x) because cosine is an even function. So we see that
(π2−2x)=±3x
i)
π2=5x
x=π10
ii)
π2=−x
x=−π2
Similarly, sin(2x)=sin(2x−2π)=cos(π2−2x−2π)
So we see that
(π2−2x−2π)=±3x
iii)
π2−2π=5x
x=−310π
iv)
π2−2π=−x
x=2π−π2=32π
Finally, we note that the solutions must repeat every 2π because the original functions each repeat every 2π. (The sine function has period π so it has completed exactly two periods over an interval of length 2π. The cosine has period 23π so it has completed exactly three periods over an interval of length 2π. Hence, both functions repeat every 2π2π2π so every solution will repeat every 2π.)
So we get ∀n∈N
i) x=π10+2πn
ii) x=−π2+2πn
iii) x=−310π+2πn
(Note that solution (iv) is redundant since 32π+2πn=−π2+2π(n+1).)
So we conclude that there are really three solutions and then the periodic extensions of those three solutions.
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Related Questions (More Answers Below)
Answer:
625 minutes
Step-by-step explanation:
Given that:
Time taken to tie 4 ribbons = 10 minutes
Number of ribbons to be tied = 250
To find:
Time taken to tie 250 ribbons.
Solution:
First of all, we need to find the time taken to tie one ribbon.
And then we can multiply it with 250 to find the time taken to tie all the 250 ribbons.
For finding the time to tie one ribbon, we need to divide the time taken to tie 4 ribbons with 4.
Time taken to tie 1 ribbon = 
minutes
Time taken to tie 250 ribbons = 2.5 
250 = <em>625 minutes</em>
Hello,
Let P(x) the first polynomial, degree P(x)=p
Q(x) the second degree Q(x)=
degree (P(x)*Q(x))=p*q
Max terms: p*q+1
(x²+x+2)(x²-2x+3)=x^4+2x^3+3x²-x+6
