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2 years ago

The linear equation y=mx+b contains the point (-5, 5) and is perpendicular to the line 5x+25y=11.

1 answer:

7 0

The linear equation y=mx+b containing the point (-5, 5) and perpendicular to the line 5x+25y=11 is y = -5/11 x + 30/11

The formula for finding the equation of a line in point-slope form is expressed as:

y-y0 = m(x-x0) where:

m is the slope

(x0, y0) is any point on the line

Given the following

(x0, y0) = (-5, 5)

Get the slope of the given line 5x+25y=11.

Rewrite in the form y = mx+b

25y = -5x + 11

y = -5/11 x + 11/25

Compare with the original equation

mx = -5/11 x

m = -5/11

Get the required equation

y - 5 = -5/11(x-(-5))

11(y-5) = -5(x+5)

11y-55 = -5x - 25

11y+5x = -25 + 55

11y+5x = 30

11y = -5x + 30

y = -5/11 x + 30/11

Hence the linear equation y=mx+b containing the point (-5, 5) and perpendicular to the line 5x+25y=11 is y = -5/11 x + 30/11

Learn more here: brainly.com/question/17003809

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Given that

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Need to find the relationship between volume of cylinder and cone.

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Calculation of volume of cylinder :

Formula of volume of cylinder is given as:

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Where π=3.14

$\text { radius } r=\frac{\text {diameter}}{2}=\frac{10}{2}=5 \text { inches }$

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On substituting given values in formula of cylinder we get

$\begin{array}{l}{V_{c y}=3.14 \times 5^{2} \times 12=942 \text { cubic inches }} \\\\ {\text { Volume of cylinder }=V_{c y}=942 \text { cubic inches }}\end{array}$

Calculation of volume of cone:

Formula of volume of cone is given as:

$V_{c o}=\frac{\pi r^{2} h}{3}$

Here π=3.14

$\begin{array}{l}{\text { radius } r=\frac{\text { diameter }}{2}=\frac{10}{2}=5 \text { inches }} \\\\ {\text { height } \mathrm{h}=12 \text { inches }}\end{array}$