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3 years ago

7

Brainly to whoever is first and right:) - In quadrilateral ABCD, AB = BC = 1, m∠B=100°, m∠D=130°. Find BD

1 answer:

n200080 [17]3 years ago

7 0

Answer: 1

B is the center of a circle of radius 1. A and C are on the circle 100 degrees apart. So arc AC is 100 degrees. Arc AC the long way around is 360-100=260 degrees. That means any point D on arc AC will subtend a 130 degree angle. BD is a radius for all of those, and the radius is 1.

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Please help me in these simple equations

cupoosta [38]

Answer:

1. $225cm^2$

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3. $405mm^2$

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5. $495mm^2$

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Step-by-step explanation:

1. Square

$A=s^2$

s = 15 cm

$A=(15cm)^2\\A=225cm^2$

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2. Rectangle

$A=l*w\\A=(32mm)(17mm)\\A=544mm^2$

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3. Rectangle

$A=l*w\\A=(45mm)(9mm)\\A=405mm^2$

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$A=\frac{hb}{2}\\ A=\frac{(9cm)(15cm)}{2}\\ A=\frac{135cm^2}{2}\\ A=67.50cm^2$

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5. Triangle

$A=\frac{hb}{2}\\ A=\frac{(30mm)(33mm)}{2}\\ A=\frac{990mm^2}{2}\\ A=495mm^2$

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6. Rectangle

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4 years ago

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Read 2 more answers

Question 2 (1 point)

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Step-by-step explanation:

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