The answer here is <span>committee judged </span>
Answer:
25%
Explanation:
The child only comes out as homozygous dominant (YY) for the trait in 1/4 boxes in the Punnett Square. This translates to the child having a 25% chance of being homozygous dominant for the trait.
Answer:
a) The substrate 2 will be accumulated in the cells.
b) The enzyme E is mutated
Explanation:
a) The enzyme C has a mutation, the substrate 2 will not be turn into substrate 3 and this will cause to accumulation of 2.
b) when cells have 1,2,3 or 4 because of mutation of E non of these substrates cannot lead to 5. but ıf 5 gıven from the diet, the individuals can survive.
