<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
Answer:
Step-by-step explanation:
You have the domain. It is given as -1≤x≤1
Now all you have to do is figure out the range which is the y value. At first glance I think it might be 3, but that does not look very logical. I'll post this much of it now and be back in under an hour with a more complete answer.
Of course! How silly of me. There is a minimum of y = 1 in the range which comes from x = 0
I've included a graph so you can see how this all works.
So the range = 1 ≤ y ≤ 3
Answer:
1. vertical-line test
2.y=x
3.x
4.domain
Step-by-step explanation:
I just did it on edg and it’s right.
c = 2 × 14.6 × π = 29.2 × 3.141592 = 91.7344864 ≈ 91.7
Correct anawer: B
Answer:
I cant help but if you look up base calculators calc for vertext you justr plug in the numbers and it gives you the answer I can prolly get it for you in a sec
Step-by-step explanation:
