Question

The greater of two numbers is 6 more than 4 times the smaller. Their sum is 41. FInd the numbers.

Answer 1

Answer:

7 and 34

Step-by-step explanation:

let x and y be the 2 numbers with x > y

The 2 equations to solve are

x = 4y + 6 → (1)

x + y = 41 → (2)

Substitute x = 4y + 6 into (2)

4y + 6 + y = 41 , that is

5y + 6 = 41 ( subtract 6 from both sides )

5y = 35 ( divide both sides by 5 )

y = 7

Substitute y = 7 into (1)

x = 4(7) + 6 = 28 + 6 = 34

The 2 numbers are 7 and 34

Answer 2

7 and 34 is the answer