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Maru [420]
3 years ago
13

The greater of two numbers is 6 more than 4 times the smaller. Their sum is 41. FInd the numbers.

Mathematics
2 answers:
schepotkina [342]3 years ago
7 0

Answer:

7 and 34

Step-by-step explanation:

let x and y be the 2 numbers with x > y

The 2 equations to solve are

x = 4y + 6 → (1)

x + y = 41 → (2)

Substitute x = 4y + 6 into (2)

4y + 6 + y = 41 , that is

5y + 6 = 41 ( subtract 6 from both sides )

5y = 35 ( divide both sides by 5 )

y = 7

Substitute y = 7 into (1)

x = 4(7) + 6 = 28 + 6 = 34

The 2 numbers are 7 and 34

kenny6666 [7]3 years ago
6 0
7 and 34 is the answer
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ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
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Answer:

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Given:

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FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

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