In order to find the answer you will have too divide 58 by 18 and then divide what you get from that by 100 to get your answer.
100%/x%=58/18
(100/x)*x=(58/18)*x
100=3.22222222222*x
(3.22222222222) to get x
100/3.22222222222=x
x=31.0344827586
Therefore your answer is "31%."
Hope this helps.
Well the actual answer is 6x=6788. Na I’m just kidding juss needa stack up these points✨
Answer:
The equation i.e. used to denote the population after x years is:
P(x) = 490(1 + 0.200 to the power of x
Step-by-step explanation:
This problem could be modeled with the help of a exponential function.
The exponential function is given by:
P(x) = ab to the power of x
where a is the initial value.
and b=1+r where r is the rate of increase or decrease.
Here the initial population of the animals are given by: 490
i.e. a=490
Also, the rate of increase is: 20%
i.e. r=20%
i.e. r=0.20
Hence, the population function i.e. the population of the animals after x years is:
P(x) = 490(1 + 0.200 to the power of x
144=(x+7)^2 take the square root of both sides...
12=x+7 subtract 7 from both sides...
x=5
So the original was a 5m square.
...
255=WL and you are told that W=L+2 so the equation becomes:
255=(L+2)L
255=L^2+2L
L^2+2L-255=0
L^2+17L-15L-255=0
L(L+17)-15(L+17)=0
(L-15)(L+17)=0 Since L>0...
L=15yd, and since W=L+2, W=17yd so
length=15, width=17yd
