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3 years ago

Which is the correct formula to find the distance between two points (p,q) and (m,n)?

Mathematics

2 answers:

GuDViN [60]3 years ago

8 0

Answer:

The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

Step-by-step explanation:

Dafna1 [17]3 years ago

6 0

Answer:

The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

Step-by-step explanation:

* The distance between any to points (x1 , y1) , (x2 , y2) is

- d = √[square the difference of x- coordinates plus

square the difference of y-coordinates]

∴ d = √[(x2 - x1)² + (y2 - y1)²] or

∴ d² = (x2 - x1)² + (y2 - y1)²

* x2 - x1 is the horizontal distance (h) and y2 - y1

is the vertical distance (v)

- By using Pythagoras theorem

∴ d = √[h² + v²]

∵ The two points are (p , q) and (m , n)

- Put x1 = m and y1 = n

- Put x2 = p and y2 = q

∴ d² = (p - m)² + (q - n)²

∴ d = √[(p - m)² + (q - n)²]

∴ The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

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3x+7-6=(8/7)-0<br>Value of x?

ArbitrLikvidat [17]

Answer:

$\boxed{\sf x = \dfrac{1}{21}}$

Explanation:

$\rightarrow \sf 3x+7-6= \dfrac{8}{7} - 0$

simplify the following

$\rightarrow \sf 3x+1= \dfrac{8}{7}$

subtract 1 from both sides

$\rightarrow \sf 3x+ 1 -1= \dfrac{8}{7} - 1$

simplify the following

$\rightarrow \sf 3x= \dfrac{1}{7}$

multiply both sides by 1/3

$\rightarrow \sf 3x \cdot \dfrac{1}{3}= \dfrac{1}{7}\cdot \dfrac{1}{3}$

simplify the following

$\rightarrow \sf x = \dfrac{1}{21}$

5 0

2 years ago

Read 2 more answers

Pretest: Unit 5 Question 12 of 21 Use the substitution method to solve the system of equations. Choose the correct ordered pair.

Gala2k [10]

Answer:

(10, - 9 )

Step-by-step explanation:

Given the 2 equations

y = - 2x + 11 → (1)

y = - 3x + 21 → (2)

Substitute y = - 2x + 11 into (2)

- 2x + 11 = - 3x + 21 ( add 3x to both sides )

x + 11 = 21 ( subtract 11 from both sides )

x = 10

Substitute x = 10 into either of the 2 equations and evaluate fir y

Substituting into (1)

y = - 2(10) + 11 = - 20 + 11 = - 9

solution is (10, - 9 )

3 0

3 years ago

Which expressions are equivalent to the given expression 6x-18y+36

umka21 [38]

Answer:

6(x-3y+6)

Step-by-step explanation:

6 0

3 years ago

Guys, Can you please help me with these questions

MakcuM [25]

Answer:

a) $w^{13} x^{5} y^{6}$

b) $\frac{x}{3y^{6} }$

Step-by-step explanation:

a) $(w^{2} xy^{3} )^{2}(w^{3}x )^{3}$

1. Distribute the second power (2) outside the first pair of parenthesis:

$(w^{2(2)} x^{2} y^{3(2)} )$

= $w^{4} x^{2} y^{6} (w^{3}x )^{3}$

2. Distribute the third power (3) outside the second pair of parenthesis:

$(w^{3(3)} x^{3} )$

= $w^{4} x^{2} y^{6} w^{9} x^{3}$

3. Combine like terms:

$w^{13} x^{5} y^{6}$

--------------------------------------------

b) $\frac{2x^{2} y^{5} }{6xy^{11} }$

1. Factor the number 6 (= 2 · 3):

$\frac{2x^{2} y^{5} }{2(3)xy^{11} }$

2. Cancel the common factor (2):

$\frac{x^{2} y^{5} }{3xy^{11} }$

3. Cancel out $xy^{5}$ in the numerator an denominator:

$\frac{x}{3y^{6} }$

hope this helps!

4 0

2 years ago

Point J has coordinates (–3, 4) in the coordinate plane. Point K has coordinates (3, 4). Both points will be reflected across th

kumpel [21]

The location of the image of points <em>J </em>and <em>K </em>following a reflection across the x-axis are;

J'(-3, -4), and K'(3, -4)

<h3>Which method can be used to find the image of a point following a reflection?</h3>

Coordinates of point are;

J(-3, 4), K(3, 4)

The given transformation is; A reflection across the x-axis

The representation of a reflection across the x-axis is presented as follows;

(x, y) → (x, -y)

The image of <em>J </em>and <em>K </em>following a transformation across the x-axis are therefore;

J(-3, 4) → J'(-3, -4)

K(3, 4) → K'(3, -4)

Learn more about reflection transformation on the coordinate plane here:

brainly.com/question/8242111

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2 years ago