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Serga [27]
3 years ago
5

Mai bought gas for her car. Gas cost $2.95 per gallon Mai bought 8.2 gallons What was the total cost for Mai's gas?

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer: $24.19

Step-by-step explanation:

From the question, we are informed that Mai bought gas for her car which cost $2.95 per gallon and that she bought 8.2 gallons.

The total cost for Mai's gas will be:

= $2.95 × 8.2

= $24.19

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A mule deer can run one over four of a mile in 25 seconds. At this rate, which expression can be used to determine how fast a mu
kondor19780726 [428]

the answer is D. twenty-five seconds over one-fourth mile = 100 miles per hour.


3 0
2 years ago
I need to find the answer for "x" 2x + 3(5x - 7) =47
nordsb [41]

Answer:

The answer would be x=4.  

Step-by-step explanation: Step 1: Simplify both sides of the equation.

2x+3(5x−7)=47

2x+(3)(5x)+(3)(−7)=47(Distribute)

2x+15x+−21=47

(2x+15x)+(−21)=47(Combine Like Terms)

17x+−21=47

17x−21=47

Step 2: Add 21 to both sides.

17x−21+21=47+21

17x=68

Step 3: Divide both sides by 17.

17x/17=68

17x=68

x=4

4 0
2 years ago
Jacob buys for muffins for $5 what is the cost of 7 muffins​
Lyrx [107]

Answer:

35$

Step-by-step explanation:

If one muffin is 5 dollars and you buy 7 then just multiple them and get 5x7=35

8 0
3 years ago
Read 2 more answers
Can someone help me please
telo118 [61]
It's a reflection across the x axis, so the y intercept won't change (12)

f (x) = 3x + 12
 |
\/
g(x) = -3x + 12

I MAY BE WRONG IM ONLY 80% SURE
8 0
2 years ago
In a survey sample of 83 respondents, the mean number of hours worked per week is 39.04, with a standard deviation of 11.51. Cal
soldier1979 [14.2K]

Given that,

Sample size= 83

Mean number= 39.04

Standard deviation= 11.51

We know the critical t-value for  95% confidence interval which is equal to 1.989.

We also know the formula for confidence interval,

CI=( mean number - critical t-value*standard deviation/(sample size)^(1/2), mean number + critical t-value*standard deviation/(sample size)^(1/2))

So, we have

CI= (39.04 - 1.989*11.51/83^(1/2), 39.04 + 1.989*11.51/83^(1/2)

CI= (39.04 - 2.513,39.04 + 2.513)

CI= (36.527,41.553)

Therefore, 95% confidence interval for these data is (36.527,41.553), and this result interpret that the true value for this survey sample lie in the interval (36.527,41.553).

8 0
3 years ago
Read 2 more answers
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