3 plus the product of 2 and h

What is the slope of the line that passes through the pair of points? (5,2) and (7,8) the answers are 2/3,-2/3,3/2 or -3/2

Mice21 [21]

Answer: The slope is: "3" ; which does not appear among the answer choices given.
______________________________________________

The slope, "m" is calculated as follows:
___________________________________
Given two coordinates on a line;

m = (y₂ − y₁) / (x₂ − x₁) ;
__________________________________________

We are given the following 2 (TWO) coordinates:
__________________________________________
1) (5,2) ; which is: (x₁ ,y₁) ; so x₁ = 5 ; y₁ = 2 ; AND:

2) (7,8); which is: (x₂ ,y₂) ; so x₂ = 7; y₂ = 8 ;
_____________________________________________
So; m = (y₂ − y₁) / (x₂ − x₁) = (8−2) /.(7−5) = 6/2 = 3 .

m = 3. The slope is: 3 ; which does not appear among the answer choices given.
______________________________________________
Alternately,
______________________________________________
We are given the following 2 (TWO) coordinates:
__________________________________________
1) (7,8) ; which is: (x₁ ,y₁) ; so x₁ = 7 ; y₁ = 8 ; AND:

2) (5,2); which is: (x₂ ,y₂) ; so x₂ = 5; y₂ = 2 ;
______________________________________________
So; m = (y₂ − y₁) / (x₂ − x₁) = (2−8) / (5−7) = -6/-2 = 3 .

m = 3. The slope is 3 ; which does not appear among the answer choices given.
________________________________________________

6 0

3 years ago

What is the simplified form of the following expression?

kogti [31]

Answer:

$\sqrt{3}$

Step-by-step explanation:

We will be using 2 properties of radicals in this simplification (outlined below).

$\sqrt{a*b}=\sqrt{a}* \sqrt{b}$
$\sqrt{a}*\sqrt{a}=a$

Let's simplify this:

$2\sqrt{27} +\sqrt{12} -3\sqrt{3}-2\sqrt{12}\\ =2\sqrt{9*3}+\sqrt{4*3} -3\sqrt{3}-2\sqrt{4*3} \\=2\sqrt{9} \sqrt{3} +\sqrt{4} \sqrt{3}-3\sqrt{3}-2\sqrt{4} \sqrt{3} \\=2(3)\sqrt{3}+(2)\sqrt{3} -3\sqrt{3}-2(2)\sqrt{3} \\ =6\sqrt{3} +2\sqrt{3}-3\sqrt{3}-4\sqrt{3} \\=\sqrt{3}$

First answer choice is right.

5 0

4 years ago

Find the value of x. Round your answer to the nearest degree.

Lostsunrise [7]

Answer:

x = 20.92°

Step-by-step explanation:

AB² + BC² = AC²

5² + BC² = 14²

BC = 3√19

$\tan(ACB) = \frac{AB}{BC}$

$\tan(x) = \frac{5}{3 \sqrt{19} }$

x = 20.925° ≈ 20.92°

HOPE THIS HELPS AND HAVE A NICE DAY <3

8 0

2 years ago

The weekly amount of money spent on maintenance and repairs by a company was observed, over a long period of time, to be approxi

ANEK [815]

Answer:

$456.45 should be budgeted.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean $440 and standard deviation $10.

This means that $\mu = 440, \sigma = 10$

How much should be budgeted for weekly repairs and maintenance so that the probability the budgeted amount will be exceeded in a given week is only 0.05?

This is x for which

P(X > x) = 0.05

So this is the 100 - 5 = 95th percentile, which is X when Z has a pvalue of 0.95, so X when Z = 1.645.

$Z = \frac{X - \mu}{\sigma}$

$1.645 = \frac{X - 440}{10}$