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ZanzabumX [31]
3 years ago
11

What’s the correct explanation for this question?

Mathematics
1 answer:
Nady [450]3 years ago
7 0

Step-by-step explanation:

=> The volume of a triangular pyramid can be found using the formula V = 1/3AH where A = area of the triangle base, and H = height of the pyramid

=> The volume of a cone can be found by V = 1/3(Ab)(H) where Ab is base area and H is the height of the cone

The difference between both is that is it's base. A cone has a polygonal base while a pyramid has a tetragonal base

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

5 0
3 years ago
Read 2 more answers
Barbie is thinking of a number 20 less than one-third of the number is 72 find barbie's number
ExtremeBDS [4]
Let x = Barbie's number
1/3 x -20 = 72
1/3 x = 92
x = 92*3=276
4 0
3 years ago
Which of the following equations, where ddd is distance in miles and ttt is time in hours, represents a speed that is less than
Alexandra [31]

Answer:

c

Step-by-step explanation:

this helps

7 0
3 years ago
Read 2 more answers
Find the volume of the rectangular
Kobotan [32]

Answer:

Hope this will help you

Step-by-step explanation:

volume \: of \: rectangular \: prism = l \times b \times h \\  = 0.6 ft\times 0.8 ft\times 3.8ft \\  = 1.824 {ft}^{3}

4 0
2 years ago
Please help me asappp (will give brainiest!)
ryzh [129]

Answer:

TanФ=-1.793

Step-by-step explanation:

Sin^{2} (A) + Cos^{2} (A) = 1

Sin(A)=\sqrt{1-Cos^{2} (A)}

Tan(A) = \frac{Sin(A)}{Cos(A)}

Tan(A) =\frac{\sqrt{1-Cos^{2}(A) } }{Cos(A)} \\Tan(A) =\frac{\sqrt{1-(-.487)^{2} } }{-.487}=-1.793433202

3 0
3 years ago
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