Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.
Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2
Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2
Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2
ANSWER: 155 in^2 is the area of the poster board she has left.
Hope this helps! :)
-3x + 9 - 4 = x + 3 + 2x
-3x + 9 - 4 = 3x + 3
9 - 4 = 6x + 3
5 = 6x + 3
2 = 6x
1/3 = x
Answer:
28.740,
Step-by-step explanation:
Answer:
Length , time, mass, current, temperature, amount of mass, luminous intesity
m, sec, kg, A, K, mol, cd
Step-by-step explanation:
Seven basic SI units are used for measurement of
Meter for length
Second for time
Kilogram for mass
Ampere for current
Kelvin for temperature
Mole for amount of mass
Candela for luminous intensity
Symbols of these SI units are
m for meter
sec for second
kg for kilogram
A for ampere
K for kelvin
mol for mole
cd for candela
Step-by-step explanation:
a^2 + b^2 = c^2
(x+2)^2 + 4x^2 = (3x+4)^2
(x+2)(x+2)+ 4x^2= (3x+4)(3x+4)
x^2 + 2x + 2x + 4 + 4x^2 = 9x^2 + 12x + 12 x + 16
5x^2 + 4x + 4 = 9x^2 + 24x + 16
-4x^2 - 20x - 12 = 0
now we can use the quadratic formula
(-b±√(b²-4ac))/(2a)
I can't type all this so
.....
x = -0.697224362 or -4.302775638
AB can't be negative so it's the first one
so it's equals to 1.302775638