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3 years ago

13

if two positive integers P and Q can be expressed as p = a b square and q equals A cube B where A and B being prime numbers then

find the LCM of P and Q

1 answer:

vodka [1.7K]3 years ago

4 0

P = ab^2
q = a^3 b

p = a * b * b
q = a*a*a * b

Pairing the duplicates we have LCM = a*a*a*b*b = a^3 b^2 answer

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Each of the line segments in the word MATH are numbered in the graph below. Find the slope (as a ratio of rise over run) of each

emmasim [6.3K]

Answer/Step-by-step explanation:

7. Line 1 = undefined.

Slope of a vertical line is always undefined. The run is zero as x-coordinate remains the same.

8. Line 2 = $\frac{4}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 4}{-5 -(-8)}$

$slope = \frac{8 - 4}{-5 + 8}$

$slope = \frac{4}{3}$

9. Line 3 = $\frac{4}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 4}{-2 -(-5)}$

$slope = \frac{8 - 4}{-2 + 5}$

$slope = \frac{4}{3}$

10. Line 4 = undefined (slope of a vertical line is always undefined)

11. Line 5 = $\frac{7}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 1}{5 - 2}$

$slope = \frac{7}{3}$

12. Line 6 = $-\frac{7}{3}$

$slope = \frac{y_2 - y_1}{x_2 - x_1}$

$slope = \frac{8 - 1}{5 - 8}$

$slope = \frac{7}{-3}$

$slope = -\frac{7}{3}$

13. Line 7 = 0

An horizontal line has no rise.

14. Line 8 = 0 (slope of horizontal line is always zero)

15. Line 9 = undefined (slope of a vertical line is always undefined)

16. Line 10 = undefined (slope of a vertical line is always undefined)

17. Line 11 = 0 (slope of horizontal line is always zero)

18. Line 12 = undefined (slope of a vertical line is always undefined)

5 0

3 years ago

Solve with interval notation Solve: 5 | x − 2 | + 4 > 8

Gnesinka [82]

Answer:

x<6/5, x>14/5

Step-by-step explanation:

Steps

$5\left|x-2\right|+4>8$

$\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}$

$5\left|x-2\right|+4-4>8-4$

$\mathrm{Simplify}$

$5\left|x-2\right|>4$

$\mathrm{Divide\:both\:sides\:by\:}5$

$\frac{5\left|x-2\right|}{5}>\frac{4}{5}$

$\mathrm{Simplify}$

$\left|x-2\right|>\frac{4}{5}$

$\mathrm{Apply\:absolute\:rule}:\quad\mathrm{If}\:|u|\:>\:a,\:a>0\:\mathrm{then}\:u\:<\:-a\:\quad\mathrm{or}\quad\:u\:>\:a$

$x-2<-\frac{4}{5}\quad\mathrm{or}\quad\:x-2>\frac{4}{5}$

Show Steps

$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$

Show Steps

$x-2>\frac{4}{5}\quad:\quad x>\frac{14}{5}$

$\mathrm{Combine\:the\:intervals}$

$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$

5 0

2 years ago

If f(x)=3x-1 and g(x)=x+2,find (f-g)(x)

oksian1 [2.3K]

Answer:

$\large\boxed{(f-g)(x)=2x-3}$

Step-by-step explanation:

$(f-g)(x)=f(x)-g(x)\\\\f(x)=3x-1,\ g(x)=x+2\\\\\text{substitute:}\\\\(f-g)(x)=(3x-1)-(x+2)\\\\=3x-1-x-2\qquad\text{combine like terms}\\\\=(3x-x)+(-1-2)\\\\=2x-3$

7 0

3 years ago

gavin and marco each have equal sized pieces of rope. gavin uses 1/4 of his rope for an art project. marco uses 1/8 of his rope

marissa [1.9K]

Answer:

Gavin uses more rope.

Step-by-step explanation:

Because 1/4>1/8, since 1/4=0.25 and 1/8=0.125.

5 0

3 years ago

saul85 [17]

Answer:

9.7

Step-by-step explanation:

tan=opposite/adjacent

tan=9/adjacent

tan 43=9/x

x tan 43=9

0.9325x=9

0.9325x/0.9325=9/0.9325

=9.65

hence;

x=9.7

7 0

3 years ago