Answer:
(A)12-19
Step-by-step explanation:
To construct a frequency distribution, we follow the steps below.
1. Find the largest and smallest values.
91 and 12 respectively
Compute the Range = Maximum - Minimum=91-12=79
2. Determine the number of classes desired.
In this case, we desire 10 classes
3. Next, we find the class width by dividing the range by the number of classes and rounding up.
79÷10 = 7.9
Rounded Up, Class Width=8
4. Pick a suitable starting point less than or equal to the minimum value.
Since our minimum value is 12, we pick a class starting with 12 and give a class width of 8.
Therefore the upper and lower limits of the first class is given as:
12-19.
Answer:
Let the number be x,
x ≥ 4
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Thank You!!
Answer:
Sum (from n = 0 to n = 33) of 10 + 15 * n
Step-by-step explanation:
The sigma notation is to express an arithmetic series as a summation, in this case we can see that it starts at 10 and ends at 505.
What we can notice is that the values are increasing by 15 units, therefore that will be the proportion that accompanies "n".
Now, we must calculate, how many times is "n", in the final value, for this we subtract the initial value, that is 10 and divide it by 15.
505 - 10 = 495/15 = 33
So "n" goes up to 33
So that series is expressed like this:
Sum (from n = 0 to n = 33) of 10 + 15 * n
Answer:
- A = 1.5
- B = -1/3
- C = -4/3
Step-by-step explanation:
For A:
- A is smack in the middle of 1 and 2, so it it 1 1/2 or 1.5 (same thing)
For B:
- Each tick mark between the numbers represents 1/3
- B is on the first tick mark between 0 and -1, so therefore it is -1/3
For C:
- C is on the first tick mark between -1 and -2
- That means C is -1 1/3
- -1 1/3 = -4/3
I hope this helps!
Answer:
3.96258
Step-by-step explanation:
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